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masya89 [10]
3 years ago
6

katia makes crafts using glass jars She can buy packages of 12 jars for $9 how many jars can kitia buy with $45

Mathematics
1 answer:
kirill [66]3 years ago
4 0

Hello!

If Katia can buy packages of jars for $9, we can determine how many packages she can purchase with $45 by using the formula:

45/9 = 5

We divide the total number of money that she has by the amount of money one package of jars costs. Now, the question also asks how many jars she can buy, not just how many packages.

We know that she can buy 5 packages, and that there are 12 jars in each package. To find the total number of jars she can buy, we will multiply 5 by 12.

5 x 12 = 60

Katia can buy 60 jars with $45.

I hope this helps you! Have a lovely day!

- Mal

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Verizon [17]

Answer:

the chance that the population mean will either be less than $1,500 or above $2,100 is 10%

Step-by-step explanation:

We are 90% confident that the true population mean willl be between $1,500 and $2,100

This means that there is a 90% probability that the true population mean will be between $1,500 and $2,100.

So 100-90 = 10% probability that it is outside of this interval, that is, either be less than $1,500 or above $2,100.

So the correct answer is:

the chance that the population mean will either be less than $1,500 or above $2,100 is 10%

5 0
3 years ago
What is the sum of the first five terms of a geometric series with a1=15 and r=1/3
Solnce55 [7]

Answer:

15, 5, 5/3, 5/9, 5/27

Step-by-step explanation:

Recall, that the general form of a geometric series is

a, ar, ar², ar³, .........

where a is the first term and r is the ratio

It is given that the first time is 15, hence a = 15

also given that ratio is 1/3

hence the first 5 terms are:

15, (15)(1/3), (15)(1/3)^2, (15)(1/3)^3, (15)(1/3)^4

simplifying each term gives

15, 5, 5/3, 5/9, 5/27

6 0
3 years ago
Read 2 more answers
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LiRa [457]

Answer:

d = \sqrt{146}

Step-by-step explanation:

d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d= \sqrt{(-5-0)^2+(-9-2)^2}\\d= \sqrt{(-5)^2+(-11)^2}\\d= \sqrt{25+121}\\d= \sqrt{146}

7 0
3 years ago
Find three consecutive integers such that the sum of the first and twice the second is 80 minus three times the third
ivanzaharov [21]

Answer:

The three consecutive integers are 12, 13, 14.

Step-by-step explanation:

Encode the question in an equation. We are given two facts: (1) the three integers are consecutive, and (2) they relate to each other through a sum.

Pick any of the integers (first, second, or third) and call it n. Then write the two others correspondingly in terms of n. I pick the middle one as n, so the three consecutive integers are (n-1), n, (n+1). That's (1). As for (2), here is the fact:

(n-1)+2n = 80-3(n+1)

Lo and behold, one equation with one unknown! Easy to solve for n to give us  the middle integer, n:

(n-1)+2n = 80-3(n+1)\\3n-1= 80-3n -3\\6n =78\\n = 13

The three consecutive integers are 12, 13, 14.

3 0
4 years ago
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FinnZ [79.3K]

Answer:

A. 195 > 14.1

Step-by-step explanation:

4 0
3 years ago
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