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AleksandrR [38]
3 years ago
5

Y=9x+4 is translated 4 units , what would be the equation on a graph?

Mathematics
1 answer:
denis-greek [22]3 years ago
6 0
I noticed that this equation is in slope-intercept form (y = mx + b). M =  the slope of the line, B = the y-intercept.

If the line is translated (fancy, fancy, talk for MOVED) up. The Y-intercept would change positive (because it is moved up) by four.

4 + 4 equals...well, 8.

Hope I could help you out! If my answer is incorrect, or I provided an answer you were not looking for, please let me know.
However, if my answer is explained well and correct, please consider marking my answer as Brainliest!  :)

Have a good one.

God bless!
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Which ordered pairs lie on the graph of the exponential function f(x)=−3^2x+5 ? Select each correct answer. ​ (−2,  76) ​ ​ ​​ (
In-s [12.5K]

Plugging in values, we get that (1,-4) works.

f(1)=-3^{2*1}+5=-3^2+5=-9+5=-4


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3 years ago
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Write the integral that gives the length of the curve y = f (x) = ∫0 to 4.5x sin t dt on the interval ​[0,π​].
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Answer:

Arc length =\int_0^{\pi} \sqrt{1+[(4.5sin(4.5x))]^2}\ dx

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Step-by-step explanation:

The arc length of the curve is given by \int_a^b \sqrt{1+[f'(x)]^2}\ dx

Here, f(x)=\int_0^{4.5x}sin(t) \ dt interval [0, \pi]

Now, f'(x)=\frac{\mathrm{d} }{\mathrm{d} x} \int_0^{4.5x}sin(t) \ dt

f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}\left ( [-cos(t)]_0^{4.5x} \right )

f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}\left ( -cos(4.5x)+1 \right )

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Now, the arc length is \int_0^{\pi} \sqrt{1+[f'(x)]^2}\ dx

\int_0^{\pi} \sqrt{1+[(4.5sin(4.5x))]^2}\ dx

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5 0
3 years ago
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Answer:

72º

Step-by-step explanation:

<em>Hey there!</em>

Well the interior of a pentagon's angle is 108º,

so we do,

180 - 108 = 72º

<em>Hope this helps :)</em>

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