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laila [671]
4 years ago
11

If Christy had 81 slime buckets for her shop and her mom gave her 95 times more slime buckets.How many slime buckets does Christ

y have for her slime shop?
Mathematics
2 answers:
Dafna11 [192]4 years ago
6 0

Answer:7695

Step-by-step explanation:

81 times 95

kupik [55]4 years ago
5 0

Answer:

your answer is 176

Step-by-step explanation:

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I believe the answer would be 70 but make sure just in case.
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3 years ago
6 to power 8 / 6 to power of 6 equals what does the slash mean. How do I calculate
artcher [175]

Step-by-step explanation:

From your problem statement, I believe the equation will look like this:

\frac{6^{8}}{6^{6}}

The slash means "divided by" -- you should use division to solve this equation.

For division involving exponents with the same base, you can use the following rule:

\frac{A^{x}}{A^{y}} = A^{x - y}

Subtituting 6 for A, 8 for x and 6 for y, we get the following:

\frac{6^{8}}{6^{6}} =6^{8 - 6} = 6^{2} = 36

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3 years ago
If a number has 2 and 6 as factors then it has 12 as a factor
zhuklara [117]

Answer:

yes

Step-by-step explanation:

2,4,6,8,10,12 so on

6 0
4 years ago
Read 2 more answers
Real numbers are always rational numbers
DiKsa [7]
Yes, real numbers are always rational numbers
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3 years ago
Simplify (12a5−6a−10a3)−(10a−2a5−14a4) . Write the answer in standard form
almond37 [142]

Answer:

=14a^5+14a^4-10a^3-16a

Step-by-step explanation:

\left(12a^5-6a-10a^3\right)-\left(10a-2a^5-14a^4\right)\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=12a^5-6a-10a^3-\left(10a-2a^5-14a^4\right)\\-\left(10a-2a^5-14a^4\right):\quad -10a+2a^5+14a^4\\-\left(10a-2a^5-14a^4\right)\\\mathrm{Distribute\:parentheses}\\=-\left(10a\right)-\left(-2a^5\right)-\left(-14a^4\right)\\Apply\:minus-plus\:rules\\-\left(-a\right)=a,\:\:\:-\left(a\right)=-a\\=-10a+2a^5+14a^4\\=12a^5-6a-10a^3-10a+2a^5+14a^4

\mathrm{Simplify}\:12a^5-6a-10a^3-10a+2a^5+14a^4:\quad 14a^5+14a^4-10a^3-16a12a^5-6a-10a^3-10a+2a^5+14a^4\\Group\:like\:terms\\=12a^5+2a^5+14a^4-10a^3-6a-10a\\\mathrm{Add\:similar\:elements:}\:12a^5+2a^5=14a^5\\=14a^5+14a^4-10a^3-6a-10a\\\mathrm{Add\:similar\:elements:}\:-6a-10a=-16a\\=14a^5+14a^4-10a^3-16a

4 0
3 years ago
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