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jeka94
4 years ago
14

6500 in 2 significant figures

Chemistry
1 answer:
Lostsunrise [7]4 years ago
3 0
It is 6500 because the first two whole numbers are 6 and 5 so you change the remaining digits to zero so you get 6500
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29 Which compounds are classified as Arrhenius acids?(1) HCl and NaOH
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(4) HBr and H2SO4 is the correct answer.
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4 0
4 years ago
Please help me it’s for a test! #8 and #9
Dmitrij [34]

Answer:

1. A

2. B

Explanation:

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8 0
3 years ago
What is the molality of the solution?
castortr0y [4]

Answer:

6.6023g

Explanation:

To create a 0.247 M solution required weight of barium hydroxide.

0.247 x 171.346 =42.322g per liter

Therefore required mass for 156g of water = 42.322 x 0.156 = 6.6023g

7 0
3 years ago
2. Condensation appears on a water glass, did this water just appear? Explain.
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Answer:

When water vapor in the air comes into contact with something cool, such as the outside of a cold glass of water, its molecules slow down and get closer together. When that happens, the gaseous water vapor turns back into liquid water droplets. That's condensation.

4 0
3 years ago
Excess Ca(OH)2 is shaken with water to produce a saturated solution. The solution is filtered, and a 50.00 mL sample titrated wi
julia-pushkina [17]

<u>Answer:</u> The K_{sp} for calcium hydroxide is 5.324\times 10^{-6}

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ca(OH)_2

We are given:

n_1=1\\M_1=0.0983M\\V_1=11.22mL\\n_2=2\\M_2=?M\\V_2=50mL

Putting values in above equation, we get:

1\times 0.0983\times 11.22=2\times M_2\times 50\\\\M_2=0.011M

The concentration of Ca(OH)_2 comes out to be 0.011 M.

The balanced equilibrium reaction for the ionization of calcium hydroxide follows:

Ca(OH)_2\rightleftharpoons Ca^{2+}+2OH^-

The expression for solubility constant for this reaction follows:

K_{sp}=[Ca^{2+}][OH^-]^2

Putting the values in above equation, we get:

K_{sp}=(0.011)\times (2\times 0.11)^2

K_{sp}=5.324\times 10^{-6}

Hence, the K_{sp} for calcium hydroxide is 5.324\times 10^{-6}

6 0
3 years ago
Read 2 more answers
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