1. F(3)= -2(3)-5
-6-5
F(3)=-11
2. F(3)= -2(3)^2-4
-6^2-4
36-4
F(3)=32
3. F(x)=−2x−5
For: x=−2, f(x) is:f(−2)=(−2×−2)−5=4−5=−1
For: x=−1, f(x) is:f(−1)=(−2×−1)−5=2−5=−3
For: x=1, f(x) is:f(1)=(−2×1)−5=−2−5=−7
For: x=2, f(x) is:f(2)=(−2×2)−5=−4−5=−9
The Range is:
{−1,−3,−7,−9}
4. -80, -110
The question ask to find the rate of change of the distance from the paticle to the origin at this instant where as a particle is moving along the curve y = 5sqrt(5x+4) and base on my calculation, I came up with an answer of 254/sqrt(226). I hope you are satisfied with my answer and feel free to ask for more
Answer:
y=1/3
Step-by-step explanation:
3y+1=0
3y=-1
3y/3=-1/3
y=-1/3
Distribute and add like terms and you are good
alirghty
we can make it easier by simplifying what we can
(4v-6v)=-2v so
(-2v)-1(v-5v³)+(5v³+3)=
-2v-v+5v³+5v³+3=
10v³-3v+3
We know that
circumference=2*pi*r
for r=7 in
circumference=2*pi*7------> 14*pi in
if 360° (full circle) has a length of------------ 14*pi in
135°-----------------------------> x
x=135*14*pi/360----------> x=5.25*pi in--------> 16.49 in
the answer is
5.25*pi in or 16.49 in
