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NARA [144]
3 years ago
5

Will give brainiest for this

Mathematics
1 answer:
cluponka [151]3 years ago
3 0

Answer:

lol, u can still ask the question

Step-by-step explanation:

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Una sustancia se encuentra en 15°c pero a partir de comienzo de un experimento su temperatura disminuye de manera uniforme a raz
bija089 [108]

Answer:

1= -15 °C

2= 7 minutos y medio

Step-by-step explanation:

1= colo la temperatura va bajando 2 grados cada minuto lo único que hay que hacer es restarle 30 °C a 15 y nos da -15 ° C

2= Solo divides 15 entre 2 y ya.

6 0
3 years ago
how would you arrange four 3's so they equal the number 0 through 10? I did 0 and 1 need help with the other numbers PLEASES!!!
Harlamova29_29 [7]
3+3+3-3=6

(3+3+3-3)÷2=3

(3+3+3+3)÷3=4

(3+3+3+3)÷6=2

Is this how it works?
5 0
3 years ago
What is the correct classification of the system of equations below? 14x + 2y = 10 y + 7x = -5 parallel coincident intersecting
marissa [1.9K]
In standard form the two equations are
  7x +y = 5
  7x +y = -5

The equations describe lines that are parallel.
5 0
3 years ago
A washer and dryer cost $841 combined. The washer cost $59 less than the dryer. How much does the dryer cost?
konstantin123 [22]

Answer:

dryer cost = $450

Step-by-step explanation:

Given that:

washer + dryer = $841  ---- eq1

As washer costs $59 less than dryer So,

Dryer - $59 = washer

putting in eq1

Dryer + dryer - $59  = $841

2 dryers = $841 +$59

Dryer  = $900/2

Dryer = $450

So the cost of washer will be:

washer = dryer - $59

Washer = $450 - $59

washer = $391

i hope it will help you!

7 0
3 years ago
Read 2 more answers
(with steps please) Find the inverse Laplace transform, f(t), of the function: 16/(s-4)^3
Stells [14]

Answer:  The required inverse transform of the given function is

f(t)=8t^2e^{4t}.

Step-by-step explanation:  We are given to find the inverse Laplace transform, f(t), of the following function :

F(s)=\dfrac{16}{(s-4)^3}.

We have the following Laplace formula :

L\{t^ne^{at}\}=\dfrac{n!}{(s-a)^{n+1}}\\\\\\\Rightarrow L^{-1}\{\dfrac{1}{(s-a)^{n+1}}\}=\dfrac{t^ne^{at}}{n!}.

Therefore, we get

f(t)\\\\=L^{-1}\{\dfrac{16}{(s-4)^3}\}\\\\\\=16\times\dfrac{t^{3-1e^{4t}}}{(3-1)!}\\\\\\=\dfrac{16}{2}t^2e^{4t}\\\\\\=8t^2e^{4t}.

Thus, the required inverse transform of the given function is

f(t)=8t^2e^{4t}.

6 0
3 years ago
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