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zimovet [89]
3 years ago
7

Which equation represents a circle that contains the point (–5, –3) and has a center at (–2, 1)? Distance formula: StartRoot (x

2 minus x 1) squared + (y 2 minus y 1) squared EndRoot
Mathematics
2 answers:
pshichka [43]3 years ago
8 0

Answer:

The equation of the circle is (x+2)^2+(y-1)^2=25

Step-by-step explanation:

we know that

The equation of a circle in standard form is equal to

(x-h)^2+(y-k)^2=r^2

where

(h,k) is the center

r is the radius

step 1

Find the radius of the circle

The radius of the circle is equal to the distance from the center to any point on the circle

we have

(–5, –3) and (–2, 1)

Find the distance

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

substitute

r=\sqrt{(1+3)^{2}+(-2+5)^{2}}

r=\sqrt{(4)^{2}+(3)^{2}}

r=\sqrt{25}

r=5\ units

step 2

Find the equation of the circle

we have

r=5\ units

(h,k)=(-2,1)

substitute

(x-h)^2+(y-k)^2=r^2

(x+2)^2+(y-1)^2=5^2

(x+2)^2+(y-1)^2=25

therefore

The equation of the circle is (x+2)^2+(y-1)^2=25

Rudiy273 years ago
8 0

Answer:

(x + 2) 2 + (y – 1) 2 = 25

Step-by-step explanation:

I took it on the edg test and got it right!!

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