Answer:
b^2 + 4 a b - 2 b - 2 a^2 + -5 a
Step-by-step explanation:
Simplify the following:
-2 a (a + b - 5) + 3 (2 b - 5 a) + b (6 a + b - 8)
-2 a (-5 + a + b) = 10 a - 2 a^2 - 2 a b:
10 a - 2 a^2 - 2 a b + 3 (2 b - 5 a) + b (6 a + b - 8)
3 (2 b - 5 a) = 6 b - 15 a:
10 a - 2 a^2 - 2 a b + 6 b - 15 a + b (6 a + b - 8)
b (-8 + 6 a + b) = -8 b + 6 a b + b^2:
10 a - 2 a^2 - 2 a b - 15 a + 6 b + -8 b + 6 a b + b^2
Grouping like terms, 10 a - 2 a^2 - 2 a b - 15 a + 6 b - 8 b + 6 a b + b^2 = b^2 + (6 a b - 2 a b) + (6 b - 8 b) - 2 a^2 + (10 a - 15 a):
b^2 + (6 a b - 2 a b) + (6 b - 8 b) - 2 a^2 + (10 a - 15 a)
a b 6 + a b (-2) = 4 a b:
b^2 + 4 a b + (6 b - 8 b) - 2 a^2 + (10 a - 15 a)
6 b - 8 b = -2 b:
b^2 + 4 a b + -2 b - 2 a^2 + (10 a - 15 a)
10 a - 15 a = -5 a:
Answer: b^2 + 4 a b - 2 b - 2 a^2 + -5 a
22/25 is the answer and also waffle waffle waffle waffle waffle
<h2>
Answer:</h2>
[C] 90°.
<u>It is Because ∠ACB is formed by the diameter of the semicircle</u>.
<u>And we already know that, the angle formed by diameter measure 90° to the circle or semicircle</u>.
Answer:
a
Step-by-step explanation:
the answer is a because thats the answer.
Answer:
After how many years is the fish population 100?
x=3.97 years
Step-by-step explanation:
The fish population increases by a factor of 1.5 each year. We have the equation that represents this situation
Where x represents the number of years elapsed f(x) represents the amount of fish.
Given this situation, the following question could be posed
After how many years is the fish population 100?
So we do 
and solve for the variable x
Observe the solution in the attached graph
