Well, the first ballon appears to be halfway to the second (the second being 300 meters from the ground) so the first, being at approximately 150 meters, both away from the ground and the balloon, would have to travel a further 150 meters.
You times the denominator from 2/3 by 4 so it can be equivalent to 8/12
2/3 x 4 = 8/12-8/12=0
Answer:
0.44
Step-by-step explanation:
-3x^2 + 2y^2 + 5xy - 2y +5x^2 - 3y^2
Combine like terms
-3x^2 + 5x^2 = 2x^2 2y^2 - 3y^2 = -1y^2
2x^2 - 1y^2 + 5xy - 2y
Now plug in the solutions Note: it is easier if you have all decimals or all fractions (-1/10=-.1
2(0.5)^2 - 1(-0.1)^2 + 5(0.5)(-0.1) - 2(-0.1)
Simplify:
0.5 - 0.01 - 0.25 + 0.2
0.5 + 0.2 - 0.01 - 0.25
0.7 - 0.26
0.44
9514 1404 393
Answer:
Step-by-step explanation:
Let x and y represent the weights of the large and small boxes, respectively. The problem statement gives rise to the system of equations ...
x + y = 85 . . . . . combined weight of a large and small box
70x +50y = 5350 . . . . combined weight of 70 large and 50 small boxes
We can subtract 50 times the first equation from the second to find the weight of a large box.
(70x +50y) -50(x +y) = (5350) -50(85)
20x = 1100 . . . . simplify
x = 55 . . . . . . . divide by 20
Using this in the first equation, we can find the weight of a small box.
55 +y = 85
y = 30 . . . . . . . subtract 55
A large box weighs 55 pounds; a small box weighs 30 pounds.
