I have an answer in mind, but i'm not 100% sure. I re-read the question, and I got 2x+3.
Answer: k = -2
solution: 2kx-3k<2x+4+3kx,
-3k-4<2x+3kx-2kx,
-3k-4<(k+2)x
Since this inequality has no solution, k = -2.
Answer:
Pythagorean Theorem: a2 + b2 = c2 b. NOTE: The side “c” is always the side opposite the right angle. Side “c” is ... Each of these is a correct answer. ... Step 2: put the values into the a2 + b2 = c2 formula and do the algebra to solve for the missing ... 12) Find the height of the triangle. Assume the lengths are given in meters.
Step-by-step explanation:
For all of these we will use the Order of Operations, also known as PEMDAS, then compare the simplifed values to see if they are equal.
[a] Equivalent / Verified
(-5) * [(-7) + (-5)] = [(-5) * (-7)] + [(-5) * (-5)]
(-5) * [-12] = [35] + [25]
60 = 60
[b] Equivalent / Verified
(-7) * [(-8) + 9] = [-7 * (-8)] + [(-7) * 9]
(-7) * [1] = [56] + [-63]
-7 = -7
[c] Equivalent / Verified
(-25) * [(-7) + (-15)] = [(-25) * (-7)] + [(-25) * (-15)]
(-25) * [-22] = [175] + [375]
550 = 550
Megan:
x to the one third power =
<span>x to the one twelfth power = </span>
<span>The quantity of x to the one third power, over x to the one twelfth power is:
</span>
<span>
Since </span>
then
Now, just subtract exponents:
1/3 - 1/12 = 4/12 - 1/12 = 3/12 = 1/4
Julie:
x times x to the second times x to the fifth = x * x² * x⁵
<span>The thirty second root of the quantity of x times x to the second times x to the fifth is
</span>
<span>
Since </span>
Then
Since
Then
Since both Megan and Julie got the same result, it can be concluded that their expressions are equivalent.