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2 years ago

Write a simplified expression for the perimeter of the figure at right.

Mathematics

1 answer:

Mila [183]2 years ago

7 0

Answer:

3xup2

Step-by-step explanation:

xup2+3x=3xup2

my answer needs to be atleast 20 words long

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At 2 PM, a thermometer reading 80°F is taken outside where the air temperature is 20°F. At 2:03 PM, the temperature reading yiel

Alexeev081 [22]

Use Law of Cooling:
$T(t) = (T_0 - T_A)e^{-kt} +T_A$
T0 = initial temperature, TA = ambient or final temperature

First solve for k using given info, T(3) = 42
$42 = (80-20)e^{-3k} +20 \\ \\ e^{-3k} = \frac{22}{60}=\frac{11}{30} \\ \\ k = -\frac{1}{3} ln (\frac{11}{30})$

Substituting k back into cooling equation gives:
$T(t) = 60(\frac{11}{30})^{t/3} + 20$

At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
$T(t) = (x-80)(\frac{11}{30})^{t/3} + 80 \\ \\ 71 = (x-80)(\frac{11}{30})^{\frac{10-t}{3}} + 80$
Solve for x:
$x = -9(\frac{11}{30})^{\frac{t-10}{3}} + 80$
Sub back into original cooling equation, x = T(t)
$-9(\frac{11}{30})^{\frac{t-10}{3}} + 80 = 60 (\frac{11}{30})^{t/3} +20$
Solve for t:
$60 (\frac{11}{30})^{t/3} +9(\frac{11}{30})^{\frac{-10}{3}}(\frac{11}{30})^{t/3} = 60 \\ \\ (\frac{11}{30})^{t/3} = \frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}} \\ \\ \\ t = 3(\frac{ln(\frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}})}{ln (\frac{11}{30})}) \\ \\ \\ t = 4.959$

This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM

8 0

3 years ago

A company makes three sizes of juice bottles: small, medium, and large.

Ivahew [28]

An expression in terms of s that represents the number of large bottles is : L = $(\frac{15s}{2} /3})$

<h3>Ratio of different sizes of bottles </h3>

The company makes s small bottles every minute

let ; M represent the number of medium bottles made every minute

L represent the number of large bottles made every minute

small bottles to medium = 2 : 3

small bottles to medium = s : M

M is the unknown, so to find how many medium bottles that has been made, we must cross multiply

2M = 3s

M = $\frac{3s}{2}$ medium bottles made every minute

medium bottles to large bottles = 3 : 5

medium bottles to large bottles = M : L

where M = $\frac{3s}{2}$

The equation becomes:

3 : 5

$\frac{3s}{2}$ : L

L is the unknown, so to find how many Large bottles that has been made, we must cross multiply

3L =( $\frac{3s}{2}$ ) * 5

L = $(\frac{15s}{2} /3})$

L = ( $\frac{5}{2}$ s)

L = 2.5 s

therefore the large bottles the company makes every minute is 2.5s large bottles

we can conclude that the expression for the number of large bottles the company makes every minute with respect to s is : L = 2.5 s

Learn more about Ratio : brainly.com/question/1509142

8 0

1 year ago

molly ran 2/3 of a mile in 8 minutes . if molly runs at that speed , how long will it take her to run one mile

Tom [10]

It would take her 12 minutes because if you mutipy 2/3 by 3/2 then you get 1 (as in one mile) and then you have to do that to the other side too so then you multiply 8 by 2/3 and get 12

4 0

2 years ago

Read 2 more answers

Please help me pretty please I been stuck on this for a while now

Alecsey [184]

D because both sides have a length of 5

5 0

2 years ago

How do I show my work on this problem ? I know the answer is -8,-10 because multiple people told me but I need to show my work

Simora [160]

Step-by-step explanation:

try adding them together that'll make sense duh lol

8 0

2 years ago