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Zepler [3.9K]
3 years ago
12

Write a simplified expression for the perimeter of the figure at right.

Mathematics
1 answer:
Mila [183]3 years ago
7 0

Answer:

3xup2

Step-by-step explanation:

xup2+3x=3xup2

my answer needs to be atleast 20 words long

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What is the slope of a line perpendicular to the line with equation y = 5x – 2?
LekaFEV [45]

Answer:

- \frac{1}{5}

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 5x - 2 ← is in slope- intercept form

with slope m = 5

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{5}

4 0
3 years ago
Whats the gcf of 48 and 78
Liono4ka [1.6K]
The greatest common factor (GCF) of 48 and 78 is: 6

Factors of 48: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48
Factors of 78: 1, 2, 3, 6, 13, 26, 39

The common factors between the two numbers are 1, 2, 3, and 6, but considering 6 is the highest number out of them, it is the greatest common factor.
5 0
3 years ago
Read 2 more answers
HELP PLEASE ASAP I WILL MARK BRAINLIEST
prisoha [69]

Answer:

BC = 24

Step-by-step explanation:

FD = 36, FE = 15 and CD = 18

By secant theorem.

DE • DF = CD • DB

(36 - 15) • 36 = 18 • DB

DB = 42

BC = DB - CD

BC = 42 - 18

BC = 24

PLEASE MARK ME AS BRAINLIEST AND HAVE A NICE DAY :)

3 0
2 years ago
Which number line shows the solution to fx-5 > 3?
sp2606 [1]

Answer:

8

Step-by-step explanation:

send <em>the</em><em> </em><em>-</em><em>5</em><em> </em><em>to</em><em> </em><em>where</em><em> </em><em>the</em><em> </em><em>+</em><em>3</em><em> </em><em>is</em><em> </em><em>then</em><em> </em><em>you</em><em> </em><em>can</em><em> </em><em>now</em><em> </em><em>add</em><em> </em><em>the</em><em> </em><em>value</em><em> </em><em>together</em><em>.</em>

7 0
3 years ago
Find the area of the rectangle with a length of (x^2-2) and a width of (2x^2-x+2)
Katyanochek1 [597]
Area=legnth times width

so multiply them together use distributive property
a(b+c)=ab+ac so
in this problem
(a+b)(c+d+e)=(a+b)(c)+(a+b)(d)+(a+b)(e)

so
x^2-2 times (2x^2-x+2)=(x^2)(2x^2-x+2)-(2)(2x^2-x+2)=(2x^4-x^3+2x^2)-(4x^2-2x+4)
add like terms
2x^4-x^3+(2x^2-4x^2)-2x+4
2x^4-x^3-2x^2-2x+4


5 0
3 years ago
Read 2 more answers
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