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Juliette [100K]
3 years ago
12

Is y=x^2-6 a linear function and why

Mathematics
2 answers:
Alexxx [7]3 years ago
6 0

Answer:

NO! y=x^2-6 is nonlinear

Step-by-step explanation:

A great teacher once told me the easiest way to tell if an equation is linear or not, by just looking at it is, if you see that the equation contains an exponent then you should automatically know that it is nonlinear. Therefore the equation y=x^2-6 is nonlinear!!!

jarptica [38.1K]3 years ago
5 0

Answer:

No.

Step-by-step explanation:

No, y=x²-6 is not a linear function.

This is because all linear functions have the highest exponent of 1. Anything equation that has a variable raised to a power other than 1 is not linear.

The equation provided as the highest exponent of 2. Thus, it's not linear.

From the provided graph, we can also see that this is quadratic instead of linear. The graph is a parabola instead of a line.

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Answer:

0.35865 and 0.35867

Step-by-step explanation:

for this number, the hundreths thousandths place is

0.358659 (bolded)

so, since the 9 rounds up, the estimated number would be 0.35866

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Write an equation of the line that has a slope of 2 and y-intercept 1 in slope-intercept form.
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3 years ago
What is th quotenit for r an 12
kramer
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3 years ago
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At an ocean-side nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water t
grandymaker [24]

Answer:

(a1) The probability that temperature increase will be less than 20°C is 0.667.

(a2) The probability that temperature increase will be between 20°C and 22°C is 0.133.

(b) The probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c) The expected value of the temperature increase is 17.5°C.

Step-by-step explanation:

Let <em>X</em> = temperature increase.

The random variable <em>X</em> follows a continuous Uniform distribution, distributed over the range [10°C, 25°C].

The probability density function of <em>X</em> is:

f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.

(a1)

Compute the probability that temperature increase will be less than 20°C as follows:

P(X

Thus, the probability that temperature increase will be less than 20°C is 0.667.

(a2)

Compute the probability that temperature increase will be between 20°C and 22°C as follows:

P(20

Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.

(b)

Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:

P(X>18)=\int\limits^{25}_{18}{\frac{1}{15}}\, dx\\=\frac{1}{15}\int\limits^{25}_{18}{dx}\,\\=\frac{1}{15}[x]^{25}_{18}=\frac{1}{15}[25-18]=\frac{7}{15}\\=0.467

Thus, the probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c)

Compute the expected value of the uniform random variable <em>X</em> as follows:

E(X)=\frac{1}{2}[10+25]=\frac{35}{2}=17.5

Thus, the expected value of the temperature increase is 17.5°C.

7 0
3 years ago
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