Hi there
First find the rate of growth between
1992 and 1998
The formula is
P=Ae^rt
P the population in 1998. (76 million)
A the population in 1992 (72 million)
E constant
R rate of growth?
T time 1,998−1,992=6 years
We need to solve for r
R=[log (p/A)÷log (e)]÷t
R=(log(76÷72)÷log(e))÷6
R=0.009
Now find the population in 2012
P=Ae^rt
P ?
A 72 million
R 0.009
T 2,012−1,992=20 years
So
P=72×e^(0.009×20)
P=86.2 round your answer to get
P=86 million
Good luck!
Answer:
Step-by-step explanation:
a) 4x¹⁰ = 2² * x¹⁰
64x² = 2⁶ *x²
GCF = 2² * x² = 4x²
b) 4x¹⁰ - 64x² = 4x²*(x⁸ - 16)
=4x² *[ (x⁴)² - 4²]
= 4x² * (x⁴ + 4) (x⁴ - 4)
= 4x² * (x⁴ + 4)* [(x²)²- 2²]
=4x² * (x⁴ + 4) * (x² + 2)(x² - 2)
The answer is +12 because you add on 12
Answer:½((n/2) – ½) – ½ = 10
½(n/2) – ¼ - ½ = 10 (using the distributive property)
¼n – ¼ - ½ = 10 (multiplying to eliminate the parentheses)
¼n – ¾ = 10 (combining like terms)
¼n = 10¾ (adding ¾ to both sides of the equation)
n = 43 (dividing both sides of the equation by ¼)
Step-by-step explanation:
Let’s start by writing Josie’s first step as an expression. Dividing n by 2, then subtracting ½ from
the result would be (n/2) – ½. If we build on this expression with the information in Josie’s
second step, we get ½((n/2) – ½) – ½. Knowing the final result is 10, we can set up the equation
below, and solve for n as follows: hope this helps
We need the rates please attach a picture
