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geniusboy [140]
4 years ago
7

What is the scientific notation of 14,200,000

Mathematics
1 answer:
Scilla [17]4 years ago
8 0
1.42*10^7 is the answer
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Which of the following best describes the figure?
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a convex nonagon

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If you can do 105 pushups in 3 min how many can you do in 5 min
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175 pushups in 5 min

Step-by-step explanation:

105/3=35\\35*5=175

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Subtract (3x2-2x+5xy-7)from(8-9xy+3x2-5x)​
shepuryov [24]

Answer:

-3x-14xy+15

Step-by-step explanation:

(8-9xy+3x^2-5x)-(3x^2-2x+5xy-7)\\\\=8-9xy+3x^2-5x-(3x^2)-(-2x)-(5xy)-(-7)\\\\=8-9xy+3x^2-5x-3x^2+2x-5xy+7\\\\=(8+7)+(-9xy-5xy)+(3x^2-3x^2)+(-5x+2x)\\\\=15-14xy+0-3x\\\\=-3x-14xy+15

6 0
3 years ago
The velocity of a turtle is recorded at 1 minute intervals (in meters per second). Use the right-endpoint approximation to estim
aliina [53]

Answer:

The total distance that the turtle traveled during the 5 seconds recorded is Distance \:traveled\approx 3.838\:\frac{m}{s}

Step-by-step explanation:

To estimate distance traveled of an object moving in a straight line over a period of time, from discrete data on the velocity of the object, we use a Riemann Sum. If we have a table of values

\left\begin{array}{ccccccc}time\:=\:t_i&t_0=0&t_1&t_2&...&t_n\\velocity\:=\:v(t_i)&v(t_0)&v(t_1)&v(t_2)&...&v(t_n)\end{array}\right

where \Delta t=t_i-t_{i-1}, then we can approximate the displacement on the interval [t_{i-1},t_i] by v(t_{i}) \times\Delta t.

Therefore the distance traveled of the object over the time interval [0,t_n] can be approximated by

Distance \:traveled\approx |v(t_1)|\Delta t+|v(t_2)|\Delta t+...+|v(t_n)|\Delta t

This is the right endpoint approximation.

We are given a table of values for <em>v(t)</em>

\left\begin{array}{cccccccc}t(sec)&0&1&2&3&4&5\\v(t)&0.078&0.83&0.75&0.98&0.853&0.425\end{array}\right

Applying the right endpoint approximation formula we get,

\Delta t = 1\sec

Distance \:traveled\approx |v(t_1)|\Delta t+|v(t_2)|\Delta t+|v(t_3)|\Delta t+|v(t_4)|\Delta t+|v(t_5)|\Delta t\\\\Distance \:traveled\approx 0.83(1)+0.75(1)+0.98(1)+0.853(1)+0.425(1)\\\\Distance \:traveled\approx 3.838\:\frac{m}{s}

The total distance that the turtle traveled during the 5 seconds recorded is Distance \:traveled\approx 3.838\:\frac{m}{s}

4 0
3 years ago
HELP! WILL GIVE BRAINLIEST!
Viefleur [7K]

p+(p*(33/100))+50

It doesn't really need the parentheses around the fraction. I just did that to show you to multiply p by the fraction as a whole instead of just the numerator. It does however need the parentheses around the 'p times the fraction' bit. Good luck. Hope this helps. Sorry if it doesn't.

8 0
4 years ago
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