9514 1404 393
Answer:
a. 1.48 seconds
Step-by-step explanation:
You want to find the larger value of t such that h(t) = 10.
-16t^2 +25t +8 = 10
16t^2 -25t +2 = 0 . . . . subtract the left side to get standard form
Using the quadratic formula, we find the values of t to be ...
t = (-(-25) ± √((-25)^2 -4(16)(2)))/(2(16)) = (25±√497)/32
t ≈ 0.08 or 1.48
The ball goes in the hoop about 1.48 seconds after it is thrown.
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<em>Additional comment</em>
The quadratic formula tells us the solution to ...
ax² +bx +c = 0
is given by ...
Here, we have a=16, b=-25, c=2. Of course, our variable is t, not x, but the relation is the same.
Answer:
Look below
Step-by-step explanation:
Given that CDB is 90 degrees, ACB is 90 degrees, and ACD is 60 degrees, we can determine that DCB = 90-60 = 30 degrees.
This means triangle BCD is a 30-60-90 (angle measures) right triangle
The proportions of the sides (from smallest to largest) is
x:x√3:2x
We are given that BC = 6 cm. This means...
2x=6
x=3
This means DB is 3 cm and CD is 3√3 cm
Using the linear pair theorem, we can find that Angle CDA is 90 degrees. This means ACD is also a 30-60-90 triangle.
x=3√3
x√3=9
2x=6√3
Now we need to find AB
AB = AD + DB
AB = 9 + 3
AB = 12 cm
Answer:
a = -5
Step-by-step explanation:
15 - a = 20
Move the constant of 15 to the other side by subtracting it.
-a = 5
Divide by -1 to make a positive.
a = -5
Check.
15 - (-5) = 20
15 + 5 = 20
20 = 20
Answer:
45 $
Step-by-step explanation:
20 x 2 = 40
40 + 5 = 45
I think the answer is if you multiply. 10m X 20w= 200, now if you devide 39.37 in 200 is equal to 5.08in
