Unit cost of a ticket = Income from ticket sales / number of tickets sold:
$1250
--------------- = $6.58 per ticket
190 tickets
Again:
$1175
--------------- = $6.71
175 tickets
While ticket prices do change (usually increase) from year to year, it's unusual to see such a situation here.
Don't have any guidelines by which to determine the "fixed cost of a ticket".
If we use the cost of a ticket of 2 years ago ($6.58/ticket), then the income from the sale of 225 tickets this year would be ($6.58/ticket)(225 tickets), or $1480.50.
12!
= 12X11X10X9X8X7X6X5X4X3X2X1
479001600 I believe
Lets take a look at the options first.
option 1 and option 4 are not possible as (8x) (8x) would give us 64x^2, which is not what we want.
we’re left with option 2 & 3. when expanded, option 2 will look like :
16x^2 - 40x - 10x + 25
= 16x^2 - 50x + 25
however, we do not want the 50x. so the answer is option 3, (4x-5) (4x+5)
if you don’t want to find the answer using expanding, there is also another method of expanding.
(a+b)^2 = a^2 - b^2
in this case, 16x^2 will be a^2 and 25 will be b^2. not sure whether you’ve learn this but yea.
Answer:
84°
Step-by-step explanation:
the total angle in a straight line sum up to 180°
Answer:
Your sum = 
- 1
S = ( (-2)^n - 1), If you let n = z, then S = (-2)^z - 1
Step-by-step explanation:
I can use a formula to find the sum of the first n terms.
we have -3, 6, -12, 24, ... etc.
common ratio = r = -2
first term = -3
a_1 = -3
Then: a_n = a_1 * r ^(n -1)
a_n = (-3) * (-2)^(n - 1) is the general formula for the nth term
Sum of first n terms = S = a_1 * (r^n - 1) / (r - 1)
so...
S = (-3) * ((-2)^n - 1 )/ (-2 - 1)
which simplifies to
S = (-3) *((-2)^n - 1) / (-3)
S = ( (-2)^n - 1)
If you let n = z, then S = (-2)^z - 1
