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sertanlavr [38]
3 years ago
10

The diagram shows one way to develop the formula for the area of a circle. Pieces of a circle with radius r are rearranged to cr

eate a shape that resembles a parallelogram. Since the circumference of the circle can be represented by 2πr, and the area of a parallelogram is determined using A = bh, which represents the approximate area of the parallelogram-like figure? A = (2πr)(r) A = (2πr)(2r) A = (2πr)(r) A = (2πr)(2r)
Mathematics
2 answers:
IRINA_888 [86]3 years ago
7 0

Answer:

A = 1/2(2πr)(r)

Explanation:

The circumference of the circle, 2πr, is the measure completely around the circle.  When the pieces of the circle are rearranged, half of this circumference will be on the top of the parallelogram and half will be on the bottom.  This means the base will be 1/2(2πr).

The approximate height of the parallelogram is the radius of the circle; this makes the area

A = 1/2(2πr)(r)

Sergeu [11.5K]3 years ago
4 0

Answer: Option C.

Step-by-step explanation:

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3 years ago
-4 is less than or equal to a, and 9 is greater or equal to w
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w => -4

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Step-by-step explanation:

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4 years ago
Solution for: <br> -x + 3y -2z = 19<br> 2x + y - z = 5<br> -3x - y + 2z = -7
STatiana [176]

Answer:

x = -1 , y = 4 , z = -3

Step-by-step explanation:

Solve the following system:

{-x + 3 y - 2 z = 19 | (equation 1)

2 x + y - z = 5 | (equation 2)

-3 x - y + 2 z = -7 | (equation 3)

Swap equation 1 with equation 3:

{-(3 x) - y + 2 z = -7 | (equation 1)

2 x + y - z = 5 | (equation 2)

-x + 3 y - 2 z = 19 | (equation 3)

Add 2/3 × (equation 1) to equation 2:

{-(3 x) - y + 2 z = -7 | (equation 1)

0 x+y/3 + z/3 = 1/3 | (equation 2)

-x + 3 y - 2 z = 19 | (equation 3)

Multiply equation 2 by 3:

{-(3 x) - y + 2 z = -7 | (equation 1)

0 x+y + z = 1 | (equation 2)

-x + 3 y - 2 z = 19 | (equation 3)

Subtract 1/3 × (equation 1) from equation 3:

{-(3 x) - y + 2 z = -7 | (equation 1)

0 x+y + z = 1 | (equation 2)

0 x+(10 y)/3 - (8 z)/3 = 64/3 | (equation 3)

Multiply equation 3 by 3/2:

{-(3 x) - y + 2 z = -7 | (equation 1)

0 x+y + z = 1 | (equation 2)

0 x+5 y - 4 z = 32 | (equation 3)

Swap equation 2 with equation 3:

{-(3 x) - y + 2 z = -7 | (equation 1)

0 x+5 y - 4 z = 32 | (equation 2)

0 x+y + z = 1 | (equation 3)

Subtract 1/5 × (equation 2) from equation 3:

{-(3 x) - y + 2 z = -7 | (equation 1)

0 x+5 y - 4 z = 32 | (equation 2)

0 x+0 y+(9 z)/5 = (-27)/5 | (equation 3)

Multiply equation 3 by 5/9:

{-(3 x) - y + 2 z = -7 | (equation 1)

0 x+5 y - 4 z = 32 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Add 4 × (equation 3) to equation 2:

{-(3 x) - y + 2 z = -7 | (equation 1)

0 x+5 y+0 z = 20 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Divide equation 2 by 5:

{-(3 x) - y + 2 z = -7 | (equation 1)

0 x+y+0 z = 4 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Add equation 2 to equation 1:

{-(3 x) + 0 y+2 z = -3 | (equation 1)

0 x+y+0 z = 4 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Subtract 2 × (equation 3) from equation 1:

{-(3 x)+0 y+0 z = 3 | (equation 1)

0 x+y+0 z = 4 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Divide equation 1 by -3:

{x+0 y+0 z = -1 | (equation 1)

0 x+y+0 z = 4 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Collect results:

Answer:  {x = -1 , y = 4 , z = -3

6 0
4 years ago
If four is subtracted from twice a number, the result is fourteen what is the equation ​
never [62]

Answer:

2x - 4 = x - 10

Step-by-step explanation:

4 0
3 years ago
What is the value of the expression (23 — 1) + 32?​
wlad13 [49]

Answer:

54

Step-by-step explanation:

Since there are parantheses or however you spell them, by using PEMDAS, we do the parantheses first.

23 - 1 = 22

Now, we do the addition.

22 + 32 = 54

4 0
3 years ago
Read 2 more answers
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