Answer:
The sample size required is at least 171
Step-by-step explanation:
We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of .
So it is z with a pvalue of , so
Now, find the margin of error M as such
In which is the standard deviation of the population and n is the size of the sample.
What sample size is required?
A samle size of at least n is required, in which n is found when
So
Rouding up
The sample size required is at least 171
This is an exponential growth/decay problem. It has a formula, and it doesn't matter which you have...the formula is the same for both, except for the fact that you're rate is decreasing instead of increasing so you will use a negative rate. The formula is this: A = Pe^rt, where A is the ending amount, P is the beginning amount, e is euler's number, r is the rate at which something is growing or dying, and t is the time in years. Our particular formula will look like this: A = 2280e^(-.30*3), Notice we have a negative number in for the rate (and of course it's expressed as a decimal!). First simplify the exponents: -.30*3 = -.9. On your calculator you have a 2nd button and a LN button. When you hit 2nd-->LN you have "e^( " on your display. Enter in -.9 and hit enter. That should give you a display of .4065695. Now multiply that by 2280 to get 926.98, the value of the computer after it depreciates for 3 years at a rate of 30% per year.
145=10x-8x it’s A I’m pretty sure
(2x-3y)^5
(2x-3y)(2x-3y)(2x-3y)(2x-3y)(2x-3y)
1st and 2nd power :
(2x-3y)(2x-3y) = 2x(2x-3y)-3y(2x-3y) = 4x² - 6xy - 6xy + 9y²
= 4x² - 12xy + 9y²
3rd power:
(2x-3y)(4x² - 12xy + 9y²) = 2x(4x² - 12xy + 9y²) - 3y(4x² - 12xy + 9y²)
8x³ - 24x²y + 18xy² - 12x²y +36xy² - 27y³
8x³ - 24x²y - 12x²y + 18xy² + 36xy² - 27y³
8x³ - 36x²y + 54xy² - 27y³
4th power
(2x-3y)(8x³ - 36x²y + 54xy² - 27y³) = 2x(8x³ - 36x²y + 54xy² - 27y³) -3y(8x³ - 36x²y + 54xy² - 27y³) = 16x^4 - 72x³y + 108x²y² - 54xy³ - 24x³y + 108x²y² - 162xy³ + 81y^4
16x^4 - 72x³y - 24x³y + 108x²y² + 108x²y² - 54xy³ - 162xy³ + 81y^4
16x^4 - 96x³y + 216x²y² - 216xy³ + 81y^4
5th power
(2x-3y)(<span>16x^4 - 96x³y + 216x²y² - 216xy³ + 81y^4)
2x(</span>16x^4 - 96x³y + 216x²y² - 216xy³ + 81y^4) - 3y(<span>16x^4 - 96x³y + 216x²y² - 216xy³ + 81y^4)
= 32x^5 - 192x^4y + 432x</span>³y² - 432x²y³ + 162xy^4 - 48x^4y + 288x³y² - 648x²y³ + 648xy^4 - 243y^5
32x^5 - 192x^4y -48x^4y + 432x³y² + 288x³y² - 432x²y³ - 648x²y³ + 162xy^4 + 648xy^4 - 243y^5
32x^5 - 240x^4y + 720x³y² - 1,080x²y³ + 810xy^4 - 243y^5
Answer:
The newborn grew by forty-five percent.
Step-by-step explanation:
(16-11)/11 * 100
= 5 / 11 * 100
= 0.454545... * 100
≅45 %