What is the sum of an 8-term geometric series if the first term is −11, the last term is 859,375, and the common ratio is −5? −1
43,231 −36,047 144,177 716,144
1 answer:
Answer:
The sum of geometric series is 716144
Step-by-step explanation:
Given
First term=a_1= -11
Last term=a_8=859375
Common ration of geometric series=r= -5
And
Total terms in geometric sequence=n=8
We know that the formula for sum of geometric series is:
S_n= (a_1 (1-r^n))/(1-r)
= (-11(1-(-5)^8)/(1-(-5))
= (-11(1-5^8))/(1+5)
= (-11(1-390625))/6
=(-11(-390624)))/6
=4296864/6
=716144
So the sum of geometric series is: 716144 ..
You might be interested in
Answer:
-80\112 = -5\7
we divided both numbers by 16
The answer to this question is going to be letter B
Answer:
after 13 months
Step-by-step explanation:
........ur welcome..........
1475-500=975
975÷75=13
so 13 months
That is a perpendicular bisector
4/24= 1/6
(1/6)*84= 14 had nuts
20/24= 5/6
(5/6)* 84 = 70 no nuts