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lbvjy [14]
3 years ago
11

HELP PLEASE ALGEBRA QUADRATICS WILL GIVE BRAINLIST

Mathematics
2 answers:
BaLLatris [955]3 years ago
4 0

Answer:

A

Step-by-step explanation:

Given a quadratic equation in standard form : ax² + bx + c = 0

Then the discriminant Δ = b² - 4ac informs us about the nature of the roots.

• If b² - 4ac > 0 then 2 real, distinct roots

• If b² - 4ac = 0 then 2 real , equal roots

• If b² - 4ac < 0 then 2 non real roots

x² + 6x + 14 = 0 ← is in standard form

with a = 1, b = 6, c = 14, then

b² - 4ac = 6² - (4 × 1 × 14) = 36 - 56 = - 20

Since b² - 4ac < 0 then 2 non real roots → A

Stolb23 [73]3 years ago
4 0

Answer:

-20, two non real solutions.

Step-by-step explanation:

The general form of a quadratic is ax^2 + bx +c. In this case, a=1, b=6, and c=14. Plug in the values for the discriminant: b^2 - 4ac ---> (6)^2 - 4(1)(14) ---> 36 - 56 ---> -20.

Remember, if the discriminant is positive, then there are two real solutions. If the discriminant is 0, then there is one real solution. If the discriminant is negative there are two imaginary solutions.

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1. We assume, that the number 128 is 100% - because it's the output value of the task. 
<span>2. We assume, that x is the value we are looking for. </span>
<span>3. If 128 is 100%, so we can write it down as 128=100%. </span>
<span>4. We know, that x is 51% of the output value, so we can write it down as x=51%. </span>
5. Now we have two simple equations:
1) 128=100%
2) x=51%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
128/x=100%/51%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for what is 51% of 128

128/x=100/51
<span>(128/x)*x=(100/51)*x       - </span>we multiply both sides of the equation by x
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<span>now we have: </span>
<span>51% of 128=65.28</span>
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Answer:

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Step-by-step explanation:

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3 years ago
12What mistake did the student make when solvingtheir two-step equation?(a)b) If correctly solved what should the value of be?
mixas84 [53]

Given the equation:

\frac{x}{6}+3=-18

(a) You can identify that the student applied the Subtraction Property of Equality by subtraction 3 from both sides of the equation:

\frac{x}{6}+3-(3)=-18-(3)

However, the student made a mistake when adding the numbers on the right side.

Since you have two numbers with the same sign on the right side of the equation, you must add them, not subtract them and use the same sign in the result. Then, the steps to add them are:

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Then:

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(b) The correct procedure is:

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\begin{gathered} \frac{x}{6}+3-(3)=-18-(3) \\  \\ \frac{x}{6}=-21 \end{gathered}

2. Apply the Multiplication Property of Equality by multiplying both sides of the equation by 6:

\begin{gathered} (6)(\frac{x}{6})=(-21)(6) \\  \\ x=-126 \end{gathered}

Hence, the answers are:

(a) The student made a mistake by adding the numbers -18 and -3:

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(b) The value of "x" should be:

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