Question

HELP PLEASE ALGEBRA QUADRATICS WILL GIVE BRAINLIST

Answer 1

Answer:

A

Step-by-step explanation:

Given a quadratic equation in standard form : ax² + bx + c = 0

Then the discriminant Δ = b² - 4ac informs us about the nature of the roots.

• If b² - 4ac > 0 then 2 real, distinct roots

• If b² - 4ac = 0 then 2 real , equal roots

• If b² - 4ac < 0 then 2 non real roots

x² + 6x + 14 = 0 ← is in standard form

with a = 1, b = 6, c = 14, then

b² - 4ac = 6² - (4 × 1 × 14) = 36 - 56 = - 20

Since b² - 4ac < 0 then 2 non real roots → A

Answer 2

Answer:

-20, two non real solutions.

Step-by-step explanation:

The general form of a quadratic is ax^2 + bx +c. In this case, a=1, b=6, and c=14. Plug in the values for the discriminant: b^2 - 4ac ---> (6)^2 - 4(1)(14) ---> 36 - 56 ---> -20.

Remember, if the discriminant is positive, then there are two real solutions. If the discriminant is 0, then there is one real solution. If the discriminant is negative there are two imaginary solutions.