Let the weight of soymeal be s, and let the weight of cornmeal be c.
You need a total of 280 lb, so that gives us one equation.
s + c = 280
Now we use the protein to write another equation.
The protein in s lb of soymeal is 0.14s.
The protein in c lb of cornmeal is 0.07c.
The protein in 280 lb of 0.09% protein mix is 0.09(280).
This gives us a second equation.
0.14s + 0.07c = 0.09(280)
Now we solve the two equations as a system of equations.
s + c = 280
0.14s + 0.07c = 0.09(280)
Solve the first equation for s and plug in tot eh second equation.
s = 280 - c
0.14(280 - c) + 0.07c = 25.2
39.2 - 0.14c + 0.07c = 25.2
-0.07c = -14
c = 200
Now we substitute c = 200 in the first equation to find s.
s + 200 = 280
s = 80
Answer: 200 lb of soymeal and 80 lb of cornmeal
8 pigs x 4 legs each = 32. so you need 2 ducks to give you 10 animals total. So 32 + 2 ducks with 2 legs = 36.
There are 8 pigs and 2 ducks.
Answer:
27 years
Step-by-step explanation:
Given that :
Town A:
Initial population = 14280
Rate = increase by 160 per year
Let t = time in years
Population is thus :
14280 + 160t - - - (1)
Town B:
Initial population = 24000
Rate = decrease by 200 per year
P = 24000 - 200t - - - (2)
Equate both equations :
14280 + 160t = 24000 - 200t
160t + 200t = 24000 - 14280
360t = 9720
t = 9720 / 360
t = 27
In 27 years
Step-by-step explanation:
n/6+2=0
n/6+2/1=0
find the LCM=6
n+12/6=0
cross multiply
n+12=0
n=-12
9514 1404 393
Answer:
300 g
Step-by-step explanation:
The problem statement tells us ...
36g = 0.12×d . . . . . where d represents the daily value
36g/0.12 = d = 300g . . . . divide by the coefficient of d
300 g of carbohydrates per day are recommended.
