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3 years ago

(8,-3) and (8,4) Linear functions

Mathematics

1 answer:

lesya692 [45]3 years ago

4 0

Answer:

$\displaystyle x = 8$

Step-by-step explanation:

Anything set to equal x is considered an undefined rate of change [slope], which is a vertical line. This is not a function, since it flunks the vertical line test.

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List the angles of the triangle in order from largest to smallest.

alina1380 [7]

Answer: A, C, B

Step-by-step explanation:

Because "a" has 8 across

And "c" has 10 across

and "b" has 13 across

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3 years ago

Determine the probability of landing on tails at most 33 times if you flip a fair coin 80 times. Round your answer to the neares

grigory [225]

Answer:

0.0728177272

Step-by-step explanation:

Given :

Number of flips = 80

Probability of landing on tail at most 33 times ;

Probability of landing on tail on any given flip = 1 / 2 = 0.5

This a binomial probability problem:

Hence ;

P(x ≤ 33) = p(x=0) + p(x=1) +... + p(x = 33)

Using a binomial probability calculator :

P(x ≤ 33) = 0.0728177272

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3 years ago

Type the correct answer in the box. Write your answer as a reduced fraction, using / for the fraction bar. A six-sided fair die

Schach [20]

Answer: $\bold{\dfrac{125}{1296}}$

Step-by-step explanation:

The probability of NOT getting a 4 means the probability of getting a 1, 2, 3, 5, or 6 which is 5 out of 6 = $\dfrac{5}{6}$

The probability of getting a 4 is 1 out of 6 = $\dfrac{1}{6}$

The probability of getting a 4 only on the last roll is:

NOT 4 and NOT 4 and NOT 4 and Yes 4

$\dfrac{5}{6}$ x $\dfrac{5}{6}$ x $\dfrac{5}{6}$ x $\dfrac{1}{6}$ = $\dfrac{5^3}{6^4}= \dfrac{125}{1296}$

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3 years ago

A tank initially contains 40 ounces of salt mixed in 100 gallons of water. a solution containing 4 oz of salt per gallon is then

stellarik [79]

Let $A(t)$ be the amount of salt in the tank at time $t$ . We're given that $A(0)=40$ . The rate at which this amount changes is given by

$A'(t)=\dfrac{5\text{ gal}}{1\text{ min}}\cdot\dfrac{4\text{ oz}}{1\text{ gal}}-\dfrac{5\text{ gal}}{1\text{ min}}\cdot\dfrac{A(t)\text{ oz}}{100+(5-5)t\text{ gal}}$

$A'(t)+\dfrac{A(t)}{20}=20$

$e^{t/20}A'(t)+e^{t/20}\dfrac{A(t)}{20}=20e^{t/20}$

$\bigg(e^{t/20}A(t)\bigg)'=20e^{t/20}$

$e^{t/20}A(t)=400e^{t/20}+C$

$A(t)=400+Ce^{-t/20}$

Since $A(0)=40$ , we get

$40=400+C\implies C=-360$

so that the amount of salt at time $t$ is

$A(t)=400-360e^{-t/20}$

After 20 minutes, the tank contains

$A(20)=400-360e^{-20/20}\approx267.56\text{ oz}$

6 0

3 years ago

Five integers have a mean of 8. The integers are 7, 3, 10, 13, X. Find the value of x.

Sophie [7]

Mean = (7+3+10+13+x)/5

(7+3+10+13+x)/5 = 8

(7+3+10+13+x) = 40
x = 40-7-3-10-13 =7

7 0

3 years ago