Given that the diameter: d= 0.0625 inch.
So, radius of the wire : r = 
= 0.03125 inch
Now the formula to find the cross-sectional area of wire ( circle) is:
A = πr²
= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125
=3.14 * 0.000976563
= 0.003066406
= 0.00307 (Rounded to 5 decimal places).
Hence, cross-sectional area of a wire is 0.00307 square inches.
Hope this helps you!
It would be lines that are plane and line
Answer:
1. A = 59
2. A = 43
Step-by-step explanation:
If we have a right triangle we can use sin, cos and tan.
sin = opp/ hypotenuse
cos= adjacent/ hypotenuse
tan = opposite/ adjacent
For the first problem, we know the opposite and adjacent sides to angle A
tan A = opposite/ adjacent
tan A = 8.8 / 5.2
Take the inverse of each side
tan ^-1 tan A = tan ^-1 (8.8/5.2)
A = 59.42077313
To the nearest degree
A = 59 degrees
For the second problem, we know the adjacent side and the hypotenuse to angle A
cos A = adjacent/hypotenuse
cos A = 15.3/21
Take the inverse of each side
cos ^-1 cos A = cos ^-1 (15.3/21)
A = 43.23323481
To the nearest degree
A = 43 degrees
Answer:
34
Step-by-step explanation:
First we need to do 2/3*21, which equals 14 as 3 and 21 can be simplified to 1 and 7. 7 * 2/1= 14. Then we add the 20 to 14, 20+14= 34
Answer:
<h3>The correct answer is <u>D: -30</u></h3>
