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arsen [322]
3 years ago
9

A poll is given, showing 30% are in favor of a new building project. If 10 people are chosen at random, what is the probability

that exactly 5 of them favor the new building project?
Mathematics
1 answer:
Schach [20]3 years ago
3 0

Answer:

30%

Step-by-step explanation:

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There are two precalculus sections at a high school. Mr.​ Abel's class has 14 girls and 8 ​boys, while Mr.​ Bonitz's class has 1
Gemiola [76]

Answer:

14/46

Step-by-step explanation:

4 0
3 years ago
Charlie split 78pounds of andy among 4 people. What is the unit rate in pounds per person?
serious [3.7K]

the answer of this is 19.5 pounds

8 0
3 years ago
PLEASE HELP!!!! 20 POINTS!!
GenaCL600 [577]
Sit tight, this is gonna be long!! =P

Also, for this answer, I'm assuming that the 'expressway' mentioned in your question is the top horizontal line. (In fact, that must be the expressway, since there would be no other way to solve the problem)

Okay, let's get started.
For starters, GY = 16 ft. That much is given to us in the question. GY's equivalent is BX, which is 10 ft. When the angles are mirrored like they are across the 'expressway' in this problem, they do not change, so we only need to put the dimensions to scale. If we divide 10 / 16, we see that the scale-down factor is .625, or 62.5%. With this information, we can find the length of XW.

How, you ask?

Well, let me tell you.

Again, when the angles are mirrored like this, they do not change. We can see that the 90 degree angle also does not change. The length of YZ is 20 ft. To find WX, we simply need to multiply YZ by our scaling factor of 62.5%. Doing so will give us our answer of 12.5 ft.

The expressway is 12.5 feet from point W.

I hope that helped, and I _really_ hope I did that right! =P
5 0
3 years ago
An experiment was performed to compare the abrasive wear of two different laminated materials. Twelve pieces of material 1 were
vladimir1956 [14]

Answer:

The calculated value Z= 4.8389> 1.96 at 0.05 level of significance.

The null hypothesis is rejected.

There is  significance difference between that the abrasive wear of material 1 not exceeds that of material 2 by more than 2 units

Step-by-step explanation:

<u>Step:-(1)</u>

Given data the samples of material 1 gave an average (coded) wear of 85 units with a sample standard deviation of 4

Mean of the first sample x₁⁻ =85

standard deviation of the first sample S₁ = 4

Given data the samples of material 2 gave an average of 81 and a sample standard deviation of 5.

Mean of the first sample x₂⁻ =81

standard deviation of the first sample S₂ = 5

<u>Step :-2</u>

<u>Null hypothesis: H₀:</u> there is no significance difference between that the abrasive wear of material 1 exceeds that of material 2 by more than 2 units

<u>Alternative hypothesis :H₁: </u>there is  significance difference between that the abrasive wear of material 1 exceeds that of material 2 by more than 2 units

Assume the populations to be approximately normal with equal variances.σ₁² =σ₂²

The test statistic

                     Z= \frac{x_{1} -x_{2} }{\sqrt{\frac{S^2_{1} }{n_{1} } +\frac{S^2_{2} }{n_{2} }  } }

Given  n₁=n₂=60.

                    Z= \frac{85-81 }{\sqrt{\frac{(4)^2 }{60 } +\frac{5^2 }{60}  } }

On calculation, we get

                   Z =   \frac{4}{\sqrt{0.6833} }

                   z = 4.8389

The tabulated value Z =1.96 at 0.05 level of significance.

The calculated value Z= 4.8389> 1.96 at 0.05 level of significance.

The null hypothesis is rejected.

Conclusion:-

there is  significance difference between that the abrasive wear of material 1 not exceeds that of material 2 by more than 2 units.

3 0
3 years ago
Select ALL the sets of three sides that will make a triangle.
luda_lava [24]

9514 1404 393

Answer:

  A. 2,3,4

  D 3,4,5

Step-by-step explanation:

In order for segment lengths to be able to form a triangle, the sum of the shortest two must exceed the longest.

A. 2,3,4 . . .  2 + 3 > 4 . . . can make a triangle

B. 2,3,5 . . . 2 + 3 = 5 . . . not a triangle

C. 2,3,6 . . . 2 + 3 < 6 . . . not a triangle

D 3,4,5 . . . 3 + 4 > b . . . can make a (right) triangle

E. 3,4,8 . . . 3 + 4 < 8 . . . not a triangle

6 0
3 years ago
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