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3 years ago

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The price, s, of a mountain bike at Speed Cycling is $210 less than twice the price, d, of the same bike at Downhill Racing. The

difference in price between the bike at Speed Cycling and Downhill Racing is $320. Which system of equations can be used to determine the price of the bike at each store?
A.
2s - d = 210
s - d = -320

B.
s - 2d = -210
s - d = -320

C.
2s - 2d = 210
s + d = 320

D.
s - 2d = -210
s - d = 320

1 answer:

aniked [119]3 years ago

8 0

Answer:

a

Step-by-step explanation:

hope this helps!! please mark brainliest

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A salesperson works 40 hours per week at a job where she has two options for being paid. Option A is a hourly wage of $25. Optio

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I love you euphorbia

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2 years ago

Order Of operation.

Nikolay [14]

Answer

18(2)+12(2)-4(5)

36+24-20

60-20

40

Step-by-step explanation:

since they had two-18 yard passes and two 12 yard runs, that's the first part of the expression, and then they had four penalties that cost them 5 yards, and that was the last term. When you simplify, you end up with 40 yards gained.

In math

Passes: 18(2)

Runs: 12(2)

Penalties:4(5)

equation

18(2)*12(2)-4(5)

Hope it helped

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3 years ago

Read 2 more answers

Which is the graph of the sequence defined by the function f(x + 1) = Three-fifthsf(x) when the first term in the sequence is 37

nadezda [96]

Answer: On a coordinate plane, 4 points are plotted. The points are (1, 375), (2, 225), (3, 135), (4, 81).

Step-by-step explanation:

We have the relation:

f(x + 1) = (3/5)*f(x)

such that the first term is 375

Then:

f(1) = 375.

Using the above relation, we have that:

f(1 + 1) = f(2) = (3/5)*f(1) = (3/5)*375 = 225

Then we have the pair (2, 225)

The next term is:

f(2 + 1) = f(3) = (3/5)*f(2) = (3/5)*225 = 135

Then we have the pair (3, 135)

the next term is:

f(3 + 1) = f(4) = (3/5)*f(3) = (3/5)*135 = 81

Then we have the pair (3, 81)

Then the correct option is the first one; On a coordinate plane, 4 points are plotted. The points are (1, 375), (2, 225), (3, 135), (4, 81).

9 0

3 years ago

Read 2 more answers

I need help with the first one please someone help I don’t get it!

levacccp [35]

Answer:

2.2

Step-by-step explanation:

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3 years ago

Special right triangles.

Oliga [24]

QUESTION 9

The given right angle triangle has its two legs equal to $x\:cm$ and the hypotenuse is $2\:units$ .

Using the Pythagoras theorem, we have

$x^2+x^2=2^2$

This implies that;

$2x^2=2^2$

$2x^2=4$

$x^2=2$

$x=\sqrt{2}$

$x=1.414$

$x\approx1.4\:units$

QUESTION 10

The given right angle triangle has its two legs equal to $x\:units$ and the hypotenuse is $7\:units$ .

Using the Pythagoras theorem, we have

$x^2+x^2=7^2$

This implies that;

$2x^2=7^2$

$2x^2=49$

$x^2=24.5$

$x=\sqrt{24.5}$

$x=4.95\:units$

QUESTION 11

Sam divided the square backyard into two sections along the 40ft diagonal.

Let one of the sides of the garden be $x\:units$ , then the other side of the garden is also $x\:units$ since it was a square backyard.

The diagonal is the hypotenuse which is 40ft and the two legs are $x\:units$ each.

Applying the Pythagoras Theorem, we have;

$x^2+x^2=40^2$

$2x^2=1600$

$x^2=800$

$\Rightarrow x=\sqrt{800}$

$\Rightarrow x=28.28$

The length of one side of the garden is approximately 28cm.

QUESTION 12

The hypotenuse of Nicole's right triangular support is 92cm long.

It was given that the two lengths of the triangular support are of equal length.

Let the two lengths of the triangular support be $l\:cm$ each.

We then apply the Pythagoras theorem to obtain;

$l^2+l^2=92^2$

$\Rightarrow 2l^2=8464$

$\Rightarrow l^2=4232$

$\Rightarrow l=\sqrt{4232}$

$\Rightarrow l=65.05cm$

Therefore Nicole needs $l+l=65.05cm+65.05cm\approx130cm$ of wood to complete the support.

The correct answer is A.

QUESTION 13

A 45-45-90 triangle is an isosceles right triangle.

Let the length of the two legs be $m\:inches$ each.

It was given that the hypotenuse of this triangle is $12\:inches$ .

Applying the Pythagoras Theorem, we have;

$m^2+m^2=12^2$

$\Rightarrow 2m^2=144$

$\Rightarrow m^2=72$

$\Rightarrow m=\sqrt{72}$

$\Rightarrow m=8.49$

The length of one leg of the hypotenuse is approximately 8.5 inches to 1 decimal place.

QUESTIONS 14.

It was given that the distance from home plate to first base is 90 feet.

Since the baseball field form a square, the length of the baselines are all 90ft.

We want to calculate the distance from home plate to 2nd base,which is the diagonal of the square baseball field.

Let this distance be $d\:ft$ , then using the Pythagoras theorem;

$d^2=90^2+90^2$

$d^2=8100+8100$

$d^2=16200$

$\:d=\sqrt{16200}$

$\:d=127.279$

Therefore the distance from home plate to second base is 127 ft to the nearest foot.

QUESTION 15.

The distance from third base to first base is also 127 ft to the nearest foot.

The reason is that the diagonals of a square are equal in length.

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3 years ago