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Zinaida [17]
3 years ago
10

If a box of 100 pencils costs 4.75, what should you expect to pay for 225 pencils

Mathematics
1 answer:
Vladimir [108]3 years ago
5 0
The answer is 10.6875 you divide 4. 75 and the number 100 them multiply your answer by 225  




glad to help any time

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A company makes poppy lapel pins.
mezya [45]

Answer:

<h2>The required percentage is 65.45%.</h2>

Step-by-step explanation:

The total costing is 1000 \times 1.10 = 1100

35% were given to the charity, hence 350 were given to the charity.

There are (1000 - 350) = 650 lapel pins remaining.

60% of 650 = \frac{60}{100} \times 650 = 390 werre sold for 3.00 each. Hence, earning from here is 390 \times3 = 1170.

40% of 650 = 260 were sold at 5.00 for 2. It can also be said that \frac{260}{2} = 130 were sold at 5.00 each. Earning from this section is 130 \times5 = 650

Total earning is (1170 + 650) = 1820.

Profit percentage = \frac{1820 - 1100}{1100} \times100 = \frac{720}{11} = 65.45

5 0
3 years ago
Does 3u+40+2u=6u-30-u have no solution
Bad White [126]
Yes you are correct! It doesn't have a solution which means no solution, hope this helps! :D
8 0
3 years ago
Read 2 more answers
Let f(x) = 5x ^ 2 - x + 1 and g(x) = - 3x . Evaluate the composition (fg)(1)
nlexa [21]
F(x) = 5(-3x) ^2 - (-3x) + 1
f(x) = -8x ^2 + 3x + 1
f(x) = -8x ^3 + 3x
5 0
2 years ago
Read 2 more answers
1- find the first term= ?, 90, 540, 3240
Luda [366]

Answer:

1. 15

2. 8

Step-by-step explanation:

The two sequence are geometric progression GP, because they follow a constant multiple (common ratio)

The nth term of a GP is;

Tn = ar^(n-1)

Where;

a = first term

r = common ratio

For the first sequence;

The common ratio r is

r = T3/T2 = 540/90 = 6

r = 6

T2 = ar^(2-1) = ar

T2 = 90 = ar

Substituting the values of r;

90 = a × 6

a = 90/6

a = 15

First term = 15

2. The sam method applies here.

Common ratio r = T3/T2 = 128/32 = 4

r = 4

T2 = ar^(2-1) = ar

T2 = 32 = ar

Substituting the values of r;

32 = a × 4

a = 32/4

a = 8

First term = 8

4 0
3 years ago
Can someone please help me ASAP :)
jeyben [28]
Did this a couple years ago, im kinda lost xD . sorry
4 0
3 years ago
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