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2 years ago

Convert the following repeating decimals to

Mathematics

1 answer:

adoni [48]2 years ago

3 0

16/99

8/9

2/9

do the last three have a decimal in the start?

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How many numbers greater than 10 and smaller than 25 with distinct digits can we make by using two of the digits 2, 0, 1, and 8

saul85 [17]

Answer:

Only four numbers can be formed

Step-by-step explanation:

We are to make numbers greater than 10 and less than 25

Distinct digits should be there

As such all numbers lying between 10 and 25 are

11,12,.....24

Of these the conditions are only 2, 0, 1 , 8 should be used.

First digit cannot be 0 or 8 because we want two digit numbers between 10 and 25

So first digit can be either 1 or 2

If first digit is 1, second digit can be either 2 or 8 i.e. only 12, 18

If first digit is 2, second digit can be 0 or 1 cannot be 8 i.e. only 20 , 21

Only 4 numbers can be formed

5 0

3 years ago

An electronic product contains 48 integrated circuits. The probability that any integrated circuit is defective is 0.01, and the

BigorU [14]

Answer:

0.6173 = 61.73% probability that the product operates.

Step-by-step explanation:

For each integrated circuit, there are only two possible outcomes. Either they are defective, or they are not. The integrated circuits are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

An electronic product contains 48 integrated circuits.

This means that $n = 48$

The probability that any integrated circuit is defective is 0.01.

This means that $p = 0.01$

The product operates only if there are no defective integrated circuits. What is the probability that the product operates?

This is P(X = 0). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{48,0}.(0.01)^{0}.(0.99)^{48} = 0.6173$

0.6173 = 61.73% probability that the product operates.

5 0

3 years ago

Which of the following is a polynomial function in standard form with zeros at –8, –1, and 3?

telo118 [61]

The answer is A because zeros of polynomial functions are found by setting each factor equal to zero and solving for x. The zeros of a function will be the opposite sign of the numbers inside each factor.

8 0

3 years ago

Read 2 more answers

What is the equation of the following line (0,0) and (-4,8)

Ann [662]

the equation using the point slope formula is

y=−2x

I hope this helps! :)

-Ayden

8 0

3 years ago

What type of line is PQ?