Question

Customers' sandwich choices one day at ray's lunch counter are shown.

Answer 1

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The relative frequencies missing in the table are :

ham-wheat = 0.231, cheese-wheat = 0.0.462.

rye-turkey = 0.167, rye-ham = 0.417.

Step-by-step explanation:

From the given data we have to count the frequencies of wheat and rye chosen to find the missing values.

The frequency of wheat chosen = 13.

The frequency of rye chosen = 12.

Relative Frequency can be obtained by dividing the combined frequency by the total number of data values.

Wheat combinations:

1) The frequency of ham-wheat = 3.

Then the relative frequency of ham-wheat = $\frac{3}{13}$.

The the relative frequency of ham-wheat = 0.230769 or 0.231.

2) The frequency of cheese-wheat = 6.

Then the relative frequency of cheese-wheat = $\frac{6}{13}$.

The the relative frequency of cheese-wheat = 0.4615 or 0.0.462.

Rye combinations:

1) The frequency of rye-turkey = 2.

Then the relative frequency of rye-turkey = $\frac{2}{12}$.

The the relative frequency of rye-turkey = 0.1666 or 0.167.

2) The frequency of rye-ham = 5.

Then the relative frequency of rye-ham = $\frac{5}{12}$.

The the relative frequency of rye-ham = 0.41667 or 0.417.