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3 years ago

Please help! I’ll mark you as brainliest if correct!!!!

Mathematics

2 answers:

Morgarella [4.7K]3 years ago

7 0

Answer:

.152

Step-by-step explanation:

only 14 but might be right

Lerok [7]3 years ago

5 0

125 i think because something equal something is something

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Find the missing side of this right triangle.

Alborosie

Answer:

Step-by-step explanation:

it's a 5,12,13 triangle

and we can find the sides by Pythagorean theorem:

a^2 + b^2 = root of c

25 + 144 = 169

root of 169 = 13

3 0

3 years ago

A 4th grade class took a field trip to a science museum. There are 24 students in the class. Each student

brilliants [131]

Answer:

$432

Step-by-step explanation:

Students:24

Ticket:$9

Lunchbox:$9

9+9=18

24x18=$432

4 0

3 years ago

If school ended today what is the first thing you'd do?

Katarina [22]

Answer:

hhehehehheh

Step-by-step explanation:

1.Go to home

2.Plug in the computer

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3 years ago

Find the two intersection points

bogdanovich [222]

Answer:

Our two intersection points are:

$\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)$

Step-by-step explanation:

We want to find where the two graphs given by the equations:

$\displaystyle (x+1)^2+(y+2)^2 = 16\text{ and } 3x+4y=1$

Intersect.

When they intersect, their x- and y-values are equivalent. So, we can solve one equation for y and substitute it into the other and solve for x.

Since the linear equation is easier to solve, solve it for y:

$\displaystyle y = -\frac{3}{4} x + \frac{1}{4}$

Substitute this into the first equation:

$\displaystyle (x+1)^2 + \left(\left(-\frac{3}{4}x + \frac{1}{4}\right) +2\right)^2 = 16$

Simplify:

$\displaystyle (x+1)^2 + \left(-\frac{3}{4} x + \frac{9}{4}\right)^2 = 16$

Square. We can use the perfect square trinomial pattern:

$\displaystyle \underbrace{(x^2 + 2x+1)}_{(a+b)^2=a^2+2ab+b^2} + \underbrace{\left(\frac{9}{16}x^2-\frac{27}{8}x+\frac{81}{16}\right)}_{(a+b)^2=a^2+2ab+b^2} = 16$

Multiply both sides by 16:

$(16x^2+32x+16)+(9x^2-54x+81) = 256$

Combine like terms:

$25x^2+-22x+97=256$

Isolate the equation:

$\displaystyle 25x^2 - 22x -159=0$

We can use the quadratic formula:

$\displaystyle x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

In this case, a = 25, b = -22, and c = -159. Substitute:

$\displaystyle x = \frac{-(-22)\pm\sqrt{(-22)^2-4(25)(-159)}}{2(25)}$

Evaluate:

$\displaystyle \begin{aligned} x &= \frac{22\pm\sqrt{16384}}{50} \\ \\ &= \frac{22\pm 128}{50}\\ \\ &=\frac{11\pm 64}{25}\end{aligned}$

Hence, our two solutions are:

$\displaystyle x_1 = \frac{11+64}{25} = 3\text{ and } x_2 = \frac{11-64}{25} =-\frac{53}{25}$

We have our two x-coordinates.

To find the y-coordinates, we can simply substitute it into the linear equation and evaluate. Thus:

$\displaystyle y_1 = -\frac{3}{4}(3)+\frac{1}{4} = -2$

And:

$\displaystyle y _2 = -\frac{3}{4}\left(-\frac{53}{25}\right) +\frac{1}{4} = \frac{46}{25}$

Thus, our two intersection points are:

$\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)$

6 0

3 years ago

Find the two consecutive whole numbers of 97

Ipatiy [6.2K]

Answer:

48 and 49

Step-by-step explanation:

48 + 49 = 97. Therefore the 2 numbers are 48 and 49

5 0

3 years ago