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ziro4ka [17]
3 years ago
6

PLS PLS ILL GIVE U BRAINLIST AND ALL THE POINT SPLS HELP ME OUT!!! HASS TO BE RIGHT ASAP PLS

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
3 0

Answer:

JHdl ukfjgwlSA

Step-by-step explanation:

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Suppose that you believe that contractor 1 is twice as likely to win as contractor 3 and that contractor 2 is three times as lik
Ray Of Light [21]

Answer:

probability that contractor 1,2 and 3 win is 33%,50% and 17% respectively

Step-by-step explanation:

assuming that there are no other contractors then:

probability that 1 , 2 or 3 win = 1

denoting as X= probability that contractor 3 wins , then assuming that only one wins , we have

probability that 1 , 2 or 3 win = 1

probability that contractor 1 wins + probability that contractor 2 wins + probability that contractor 3 wins = 1

2*P(X) + 3*P(X) + P(X) = 1

6*P(X) = 1

P(X) =1/6

then

-probability that contractor 1 wins = 2/6 (33%)

-probability that contractor 3 wins = 3/6 (50%)

-probability that contractor 3 wins = 1/6 (17%)

3 0
3 years ago
PLEASE HELP ITS OVERDUE PLEASE I NEED HELP!!
IgorLugansk [536]

Answer:

First question: Choice A

second question:Choice D

Third question: Choice c

Fourth question: Choise b

5th Question: choice b

5 0
2 years ago
On the scale drawing of a car, the length from bumper to bumper is 6 inches. The car"s actual length, from bumper to bumper, is
I am Lyosha [343]
Cross multiply and solve for x

6 0
3 years ago
2. Solve the<br> triangle.<br> a = 12, b = 22, C = 95°
djyliett [7]

this is the answer to this question - Two weather tracking stations are on the equator 146 miles apart. A weather balloon is located on a bearing of N 35°E from the western station and on a bearing of N 23°E from the eastern station. How far is the balloon from the western station?

Answer:

Reasons:

The given parameters are;

Distance between the two stations = 146 miles

Location of the weather balloon from the Western station = N35°E

Location of the weather balloon from the Eastern station = N23°E

The location of the station = On the equator

Required:

The distance of the balloon from the Western station

Solution:

- The angle formed between the horizontal, and the line from the Western station

to the balloon = 90° - 35° = 55°

- The angle formed between the horizontal, and the line from the Eastern station

to the balloon = 90° + 23° = 113°

The angle at the vertex of the triangle formed by the balloon and the two stations is 180° - (55 + 113)° = 12°

By sine rule,

Distance from balloon to western station = 146/sin(12 dg) = Distance from balloon to western station/sin(113 dg)

Therefore;

Distance from balloon to western station = 146/sin(12 dg) x sin(113 dg) ~ 646.4

Step-by-step explanation:

7 0
2 years ago
of devi runs 2 km along the 400- long boundry of a field to stay fit how many rounds does she runs around the boundary​
Neporo4naja [7]

Answer:

  • 5 rounds

Step-by-step explanation:

  • Total distance = 2 km
  • Boundary = one round = 400 m

<u>Number of rounds:</u>

  • 2 km / 400 m=
  • 2000 m/ 400 m =
  • 5 rounds
8 0
2 years ago
Read 2 more answers
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