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Aleks04 [339]
3 years ago
8

Question 1 (Essay Worth 10 points) (07.02 MC) The lengths of three sides of a trapezoid are shown below: Side 1: 11z2 − 4z + 2 S

ide 2: −2z + 3 + 12z2 Side 3: 3 − 3z + 13z2 The perimeter of the trapezoid is 5z3 + 40z2 + 7z − 15. Part A: What is the total length of sides 1, 2, and 3, of the trapezoid? (4 points) Part B: What is the length of the fourth side of the trapezoid? (3 points) Part C: Do the answers for Part A and Part B show that the polynomials are closed under addition and subtraction? Justify your answer. (3 points)
Mathematics
1 answer:
Maslowich3 years ago
7 0
The answer is the 3 trapsizoid as it’s interior is invert
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10. The sides of a number cube have the numbers 9, 3, 5, 3, 7, and 9. If the
ddd [48]

Answer:

1/3 or 33.333333333%

Step-by-step explanation:

Two 9's

Six number possible

2/6= 1/3

Probability:

1/3 or 33.33333333%

3 0
2 years ago
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Tacoma's population in 2000 was about 200 thousand, and had been growing by about 9% each year. a. Write a recursive formula for
KIM [24]

Answer:

a) The recurrence formula is P_n = \frac{109}{100}P_{n-1}.

b) The general formula for the population of Tacoma is

P_n = \left(\frac{109}{100}\right)^nP_{0}.

c) In 2016 the approximate population of Tacoma will be 794062 people.

d) The population of Tacoma should exceed the 400000 people by the year 2009.

Step-by-step explanation:

a) We have the population in the year 2000, which is 200 000 people. Let us write P_0 = 200 000. For the population in 2001 we will use P_1, for the population in 2002 we will use P_2, and so on.

In the following year, 2001, the population grow 9% with respect to the previous year. This means that P_0 is equal to P_1 plus 9% of the population of 2000. Notice that this can be written as

P_1 = P_0 + (9/100)*P_0 = \left(1-\frac{9}{100}\right)P_0 = \frac{109}{100}P_0.

In 2002, we will have the population of 2001, P_1, plus the 9% of P_1. This is

P_2 = P_1 + (9/100)*P_1 = \left(1-\frac{9}{100}\right)P_1 = \frac{109}{100}P_1.

So, it is not difficult to notice that the general recurrence is

P_n = \frac{109}{100}P_{n-1}.

b) In the previous formula we only need to substitute the expression for P_{n-1}:

P_{n-1} = \frac{109}{100}P_{n-2}.

Then,

P_n = \left(\frac{109}{100}\right)^2P_{n-2}.

Repeating the procedure for P_{n-3} we get

P_n = \left(\frac{109}{100}\right)^3P_{n-3}.

But we can do the same operation n times, so

P_n = \left(\frac{109}{100}\right)^nP_{0}.

c) Recall the notation we have used:

P_{0} for 2000, P_{1} for 2001, P_{2} for 2002, and so on. Then, 2016 is P_{16}. So, in order to obtain the approximate population of Tacoma in 2016 is

P_{16} = \left(\frac{109}{100}\right)^{16}P_{0} = (1.09)^{16}P_0 = 3.97\cdot 200000 \approx 794062

d) In this case we want to know when P_n>400000, which is equivalent to

(1.09)^{n}P_0>400000.

Substituting the value of P_0, we get

(1.09)^{n}200000>400000.

Simplifying the expression:

(1.09)^{n}>2.

So, we need to find the value of n such that the above inequality holds.

The easiest way to do this is take logarithm in both hands. Then,

n\ln(1.09)>\ln 2.

So, n>\frac{\ln 2}{\ln(1.09)} = 8.04323172693.

So, the population of Tacoma should exceed the 400 000 by the year 2009.

8 0
3 years ago
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Mike plans to cover a box with fabric.
Anuta_ua [19.1K]
208 is the answer good luck
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3 years ago
Which of the following does not belong?
I am Lyosha [343]

The correct option is option d

do u like bts

8 0
3 years ago
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8 is 80% of what number A. 10.0 B. 6.4 C. 0.1 D. 640.0
kaheart [24]
The correct answer is A. 10

8 divided by 0.8 = 10
10x0.8=8
3 0
3 years ago
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