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adoni [48]
3 years ago
14

Consider these four data sets.

Mathematics
2 answers:
skad [1K]3 years ago
8 0

Answer: Set C is correct answer.

Step-by-step explanation:

Symmetrical distribution is a type of distribution in which all data occurs at regular frequencies, and the measures of central tendency is occurred at same point.

Here, we can see from the options that

Set C has data with same difference i.e. 5

Here, Median would be 17 as the median is the central value after arranging the data value in ascending order.

Mean = \dfrac{2+7+12+17+22+27+32}{7}=\dfrac{119}{7}=17

∴ Mean = 17

Mode = 3 Median - 2 Mean

Mode=3\times 7-2\times 7\\\\Mode=21-14\\\\Mode=7

∴ Mode = 7

Thus, all mean, median and mode is occurred at same point i.e. 7.

Hence, Set C is correct answer.

Jlenok [28]3 years ago
7 0
Set C. because every number has a 5 difference between each other.
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Al tom and Joe share €3000. The ratio of the amount Al gets to the amount tom gets is in the ratio 5:4. Joe gets 1.5 times the a
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Answer:

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Read 2 more answers
If Vector u=(5,-7) and v=(-11,3), 2v-6u=_____ and ||2v-6u||≈_____
Sauron [17]
<h2>Answer:</h2>

2\vec{v}-6\vec{u}=(-52,48) \\ \\ ||2\vec{v}-6\vec{u}||=75.28}

<h2>Step-by-step explanation:</h2>

In this problem we have two vectors:

\vec{u}=(5,-7) \ and \ \vec{v}=(-11,3)

So we need to find two things:

2\vec{v}-6\vec{u}

and:

||2\vec{v}-6\vec{u}||

FIRST:

In this case we have the multiplication of vectors by scalars. A scalar is a simple number, so:

2\vec{v}-6\vec{u} \\ \\ Replace \ \vec{v} \ and \ \vec{u} \ by \ the \ given \ vectors: \\ \\ 2(-11,3)-6(5,-7) \\ \\ Multiply \ each \ component \ by \ the \ corresponding \ scalar:\\ \\ (2\times (-11),2\times 3)+(-6\times 5,-6\times (-7)) \\ \\ (-22,6)+(-30,42) \\ \\ Sum \ of \ vectors: \\ \\ (-22-30,6+42) \\ \\ \therefore \boxed{(-52,48)}

SECOND:

If we name:

\vec{w}=2\vec{v}-6\vec{u}

Then, ||2\vec{v}-6\vec{u}|| is the magnitude of the vector \vec{w}. Therefore:

||\vec{w}||=||2\vec{v}-6\vec{u}|| \\ \\ ||\vec{w}||=||(-52,48)|| \\ \\ ||\vec{w}||=\sqrt{(-58)^2+48^2} \\ \\ ||\vec{w}||=\sqrt{3364+2304} \\ \\ ||\vec{w}||=\sqrt{5668} \\ \\ \boxed{||\vec{w}||=75.28}

5 0
3 years ago
Read 2 more answers
Write an absolute value inequality that has 3 and -5 as two of its solutions
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