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ArbitrLikvidat [17]
3 years ago
9

Jordan works as the manager of a supermarket is paid a normal rate of $16.80 per hour for a 38 hour working week.

Mathematics
1 answer:
Rina8888 [55]3 years ago
5 0

Answer:

a) 638.40

b) 638.40+111.72=750.12

c) 750.12×4=3000.48

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I neeed the answer now
natka813 [3]

Answer:

48 laps

Step-by-step explanation:

multiply 6 by 8 then that's your answer

4 0
3 years ago
you are attempting to guess a 3 digit number and have the following information. there are no 0s the number is even. the sum of
ss7ja [257]

The 3-digit number is 132

<h3>How to determine the 3-digit number?</h3>

The given parameters are:

  • Number of digits = 3
  • Sum of digits = 6
  • No 0s in the number
  • No repeated digit

The first highlight above implies that the number can be any of 100 to 999

The other highlights imply that the no digit can appear repeatedly, the highest digit in the number is 3, and the number must end with 2.

So, we have:

X32

The first digit is the smallest.

1 is smaller than 3 and 2.

So, we have

132

Hence, the 3-digit number is 132

Read more about digits and numbers at:

brainly.com/question/26856218

#SPJ1

7 0
2 years ago
The triangle T has vertices at (-2, 1), (2, 1) and (0,-1). (It might be an idea to
Firdavs [7]

Rewrite the boundary lines <em>y</em> = -1 - <em>x</em> and <em>y</em> = <em>x</em> - 1 as functions of <em>y </em>:

<em>y</em> = -1 - <em>x</em>  ==>  <em>x</em> = -1 - <em>y</em>

<em>y</em> = <em>x</em> - 1  ==>  <em>x</em> = 1 + <em>y</em>

So if we let <em>x</em> range between these two lines, we need to let <em>y</em> vary between the point where these lines intersect, and the line <em>y</em> = 1.

This means the area is given by the integral,

\displaystyle\iint_T\mathrm dA=\int_{-1}^1\int_{-1-y}^{1+y}\mathrm dx\,\mathrm dy

The integral with respect to <em>x</em> is trivial:

\displaystyle\int_{-1}^1\int_{-1-y}^{1+y}\mathrm dx\,\mathrm dy=\int_{-1}^1x\bigg|_{-1-y}^{1+y}\,\mathrm dy=\int_{-1}^1(1+y)-(-1-y)\,\mathrm dy=2\int_{-1}^1(1+y)\,\mathrm dy

For the remaining integral, integrate term-by-term to get

\displaystyle2\int_{-1}^1(1+y)\,\mathrm dy=2\left(y+\frac{y^2}2\right)\bigg|_{-1}^1=2\left(1+\frac12\right)-2\left(-1+\frac12\right)=\boxed{4}

Alternatively, the triangle can be said to have a base of length 4 (the distance from (-2, 1) to (2, 1)) and a height of length 2 (the distance from the line <em>y</em> = 1 and (0, -1)), so its area is 1/2*4*2 = 4.

6 0
3 years ago
A large container holds 8 gallons of water. It begins leaking at a constant rate. After 32 minutes the container has 6 gallons l
anzhelika [568]

Answer:

1 gallon every 16 minutes

Step-by-step explanation:

If after 32 minutes the container has 6 gallons left that means it has lost 2 gallons of water. So we now divide the 32 minutes by the 2 gallons of water to get that 1 gallon of water leaks every 16 minutes.


8 0
3 years ago
SOMEONE PLEASE HELP<br> find the greatest common factor <br> 14g5h2, 56g3h4, 77g3h2
andrezito [222]

Answer:

\large\boxed{GCF(14g^5h^2,\ 56g^3h^4,\ 77g^3h^2)=g^3h^2}

Step-by-step explanation:

14g^5h^2=2\cdot7\cdot \boxed{g}\cdot \boxed{g}\cdot \boxed{g}\cdot g\cdot g\cdot \boxed{h}\cdot \boxed{h}\\\\56g^3h^4=2\cdot2\cdot2\cdot7\cdot\boxed{g}\cdot \boxed{g}\cdot \boxed{g}\cdot \boxed{h}\cdot \boxed{h}\cdot h\cdot h\\\\77g^3h^2=7\cdot11\cdot\boxed{g}\cdot \boxed{g}\cdot \boxed{g}\cdot \boxed{h}\cdot \boxed{h}\\\\GCF(14g^5h^2,\ 56g^3h^4,\ 77g^3h^2)=\boxed{g}\cdot \boxed{g}\cdot \boxed{g}\cdot \boxed{h}\cdot \boxed{h}=g^3h^2

8 0
3 years ago
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