A) 5000 m²
b) A(x) = x(200 -2x)
c) 0 < x < 100
Step-by-step explanation:
b) The remaining fence, after the two sides of length x are fenced, is 200-2x. That is the length of the side parallel to the building. The product of the lengths parallel and perpendicular to the building is the area of the playground:
A(x) = x(200 -2x)
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a) A(50) = 50(200 -2·50) = 50·100 = 5000 . . . . m²
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c) The equation makes no sense if either length (x or 200-2x) is negative, so a reasonable domain is (0, 100). For x=0 or x=100, the playground area is zero, so we're not concerned with those cases, either. Those endpoints could be included in the domain if you like.
(f - 7)/g = h
f - 7 = gh
f = gh + 7
Answer:
8
Step-by-step explanation:
Hope it helps
:D
Can i have brainly pls
Answers:
a= 5x±
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6
u=± 
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2
<h2>Brainliest please!!!! It took me a while to figure this out!</h2>
1. 12*100 - 12*5
You would use the distributive property to get this equation (it is equivalent to the original one)
2. Um... There's no actual story for this problem; sorry I can't solve this problem
