All categories

3 years ago

A car travels 250 km east, then turns 25° south of east and goes 115 km. What is the resultant distance traveled?

Mathematics

1 answer:

Firlakuza [10]3 years ago

4 0

Answer:

The distance traveled is 357.54km.

Step-by-step explanation:

The situation is illustrated in the figure attached.

From the law of cosines the distance $d$ is given by

$d^2 = (250km)^2+(115km)^2-2(250km)(115km)cos(155^o)$

$d^2 = 127837.698 km^2$

$\boxed{d = 357.54km}$

You might be interested in

Find a number which decreased by 24 equals 3 times it’s opposite

Nata [24]

x - 24 = 3 (-1) x

x - 24 = -3x

-24 = -4x

x = 6

Step-by-step explanation:

6 0

3 years ago

What is the speed of a bowling ball that travels 100 meters in 5 seconds

anyanavicka [17]

20 meters per second or 20 mps

6 0

3 years ago

Jamiyah and Samantha went to a grocery store and purchased a bag of 22 apples. Let x represent the Jamiyah’s portion of the appl

Serhud [2]

Answer:

Step-by-step explanation:

5 0

3 years ago

Mohamad spends $4 a week on comic books. How much LESS money will he have in 4 weeks from NOW? How much MORE money did Mohamad h

Zepler [3.9K]

Answer:

Step-by-step explanation:

So, $4x4weeks= 16

4x2=8

So he had 8 MORE money than in 4 weeks

4 0

2 years ago

There are 500 students in a high school senior class. Of these 500 students, 300 regularly wear a necklace to

andre [41]

Answer:

1. P(N) = 3/5

2. P(R) = 2/5

3. P(N and R) = 1/4

4. P(N or R) = 3/4

Step-by-step explanation:

1. Let's review the information given to us to answer the problem correctly:

Number of students in a high school senior class = 500

Number of students that regularly wear a necklace = 300

Number of students that regularly wear a ring = 200

Number of students that wear a necklace and a ring = 125

2. What is P(N), the probability that a senior wears a necklace?

Let's recall the formula of probability:

Probability = Number of favorable outcomes/Total of possible outcomes

Substituting with the real given values:

P(N) = 300/500 = 3/5 (Dividing by 100 numerator and denominator)

P(N) = 3/5

3. What is P(R), the probability that a senior wears a ring?

Substituting with the real given values:

P(R) = 200/500 = 2/5 (Dividing by 100 numerator and denominator)

P(R) = 2/5

4. What is P(N and R), the probability that a senior wears a necklace and a ring?

Substituting with the real given values:

P(N and R) = 125/500 = 1/4 (Dividing by 125 numerator and denominator)

P(N and R) = 1/4

5. What is P(N or R), the probability that a senior wears a necklace or a ring?

P(N or R) = P(N) + P(R) - P(N and R)

Substituting with the real given values:

P(N or R) = 3/5 + 2/5 - 1/4

P(N or R) = 5/5 - 1/4

P(N or R) = 1 - 1/4

P(N or R) = 3/4

5 0

3 years ago