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3 years ago

Write a quadratic function in standard form with a leading coefficient of 1 for the given set of zeros. 7 and 4

Mathematics

1 answer:

Viefleur [7K]3 years ago

6 0

We are given : Zeros x=7 and x=4 and leading coefficent 1.

In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.

For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).

So, we need to multiply (x-7) and (x-4) by foil method.

We get

(x-7)(x-4) = x*x + x* -4 -7*x -7*-4

x^2 -4x -7x +28.

Combining like terms, we get

-4x-7x = -11x

x^2 -4x -7x +28 = x^2 -11x +28.

Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.

We get

1(x^2 -11x +28) = x^2 -11x +28.

Therefore, the required quadratic function in standard form is x^2 -11x +28.

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joanne buys a rectangular rug with an area of 35/4 square meters. The length of the rug is 7/2 meters. What is thw width, in met

yuradex [85]

The width pf the rug is 15 meters

5 0

3 years ago

Solve the equation. Then check your solution

kondaur [170]

Answer:

Option B is correct i.e. 21

Step-by-step explanation:

In the question we're provided with an equation that is :

v/7 = 3

And we are asked to find the solution for the equation .

Solution : -

 $\longrightarrow \: \frac{v}{7} = 3$ 

Multiplying by 7 on both sides :

$\longrightarrow \: \frac{v}{ \cancel{7} }\times \cancel{7} = 3 \times 7$

On further calculations , we get :

$\longrightarrow \: \blue{\boxed{v = 21}}$

Therefore , solution for equation is 21 .That means option B is the correct answer.

Verifying :

We are verifying our answer by substituting value of v in the equation given in question :

$\longrightarrow \: \frac{v}{7} = 3$

Putting value of v :

$\longrightarrow \: \cancel{\frac{21}{7}} = 3$

By dividing 21 with 7 , we get :

$\longrightarrow \:3 = 3$

$\longrightarrow \: L.H.S=R.H.S$

$\longrightarrow \: Hence , \: Verified.$

Therefore , our answer is valid .

<h2>#Keep Learning</h2>

3 0

1 year ago

Read 2 more answers

What set of reflections would carry triangle ABC onto itslelf?

riadik2000 [5.3K]

<h3>Answer: Choice A</h3>

y axis, x axis, y axis, x axis

============================

Explanation:

Reflecting an object over the y axis twice will have it end up in its starting position. The same can be said for the x axis as well. It doesn't matter that the x axis reflections aren't grouped next to each other, nor the y. So in a sense, two x axis reflections undo each other, so do the y axis reflections, and we end up with the same image as shown in the diagram.

6 0

3 years ago

Plz help me with this

shtirl [24]

2x-7y=18 _(1)
-2x+4y=5

11y=23 , Y=23/11 sub in 1

2x-7×23/11=18

2x = 18×11 + 7×23

x = ( 198 + 161 )/2 = 359/2

5 0

3 years ago

P: 2,012

OleMash [197]

El volumen remanente entre la esfera y el cubo es igual a 30.4897 centímetros cúbicos.

<h3>¿Cuál es el volumen remanente entre una caja cúbica vacía y una pelota?</h3>

En esta pregunta debemos encontrar el volumen remanente entre el espacio de una caja cúbica y una esfera introducida en el elemento anterior. El volumen remanente es igual a sustraer el volumen de la pelota del volumen de la caja.

Primero, se calcula los volúmenes del cubo y la esfera mediante las ecuaciones geométricas correspondientes:

Cubo

V = l³

V = (4 cm)³

V = 64 cm³

Esfera

V' = (4π / 3) · R³

V' = (4π / 3) · (2 cm)³

V' ≈ 33.5103 cm³

Segundo, determinamos la diferencia de volumen entre los dos elementos:

V'' = V - V'

V'' = 64 cm³ - 33.5103 cm³

V'' = 30.4897 cm³

El volumen remanente entre la esfera y el cubo es igual a 30.4897 centímetros cúbicos.

Para aprender más sobre volúmenes: brainly.com/question/23940577

#SPJ1

3 0

1 year ago