Answer:
Step-by-step explanation:
In this case the first assumption is that the distribution of the age is a normal distribution, in that case and according to the theory the 2,5 standard deviation at left and rigth of the mean are de 95% of the data so if we get 36 students the standard error depends of the whole population in this case we don't have it and the probability that the mean would be larger than 19.5 is 95% because 36 minus 22 that is 2,5 standard deviation makes 14 and the probability that the mean would be between 25.5 and 27 is 95% because all the data are in that range.
The ratio would be 75:45 so there would be 75 waters and 45 sodas
Answer:
The variance of the profile is 0.2179.
Step-by-step explanation:
We are given the following in the question:
![\sigma_A = 0.5\\\sigma_B = 0.6\\\rho_{A,B} = 0.5\\w_A = 70\% = 0.7\\w_B = 30\% = 0.3](https://tex.z-dn.net/?f=%5Csigma_A%20%3D%200.5%5C%5C%5Csigma_B%20%3D%200.6%5C%5C%5Crho_%7BA%2CB%7D%20%3D%200.5%5C%5Cw_A%20%3D%2070%5C%25%20%3D%200.7%5C%5Cw_B%20%3D%2030%5C%25%20%3D%200.3)
Variance of portfolio is given by:
![w_A^2\sigma_A^2 +w_B^2\sigma_B^2 + 2w_Aw_BCov_{A,B}](https://tex.z-dn.net/?f=w_A%5E2%5Csigma_A%5E2%20%2Bw_B%5E2%5Csigma_B%5E2%20%2B%202w_Aw_BCov_%7BA%2CB%7D)
![Cov_{A,B} = \rho_{A,B} \times \sigma_A \times \sigma_B \\=0.5\times 0.5 \times 0.6\\=0.15](https://tex.z-dn.net/?f=Cov_%7BA%2CB%7D%20%3D%20%5Crho_%7BA%2CB%7D%20%5Ctimes%20%5Csigma_A%20%5Ctimes%20%5Csigma_B%20%5C%5C%3D0.5%5Ctimes%200.5%20%5Ctimes%200.6%5C%5C%3D0.15)
Putting values, we get,
![w_A^2\sigma_A^2 +w_B^2\sigma_B^2 + 2w_Aw_BCov_{A,B}\\=(0.7)^2(0.5)^2 + (.3)^2(0.6)^2 + 2(0.7)(0.3)(0.15)\\=0.2179](https://tex.z-dn.net/?f=w_A%5E2%5Csigma_A%5E2%20%2Bw_B%5E2%5Csigma_B%5E2%20%2B%202w_Aw_BCov_%7BA%2CB%7D%5C%5C%3D%280.7%29%5E2%280.5%29%5E2%20%2B%20%28.3%29%5E2%280.6%29%5E2%20%2B%202%280.7%29%280.3%29%280.15%29%5C%5C%3D0.2179)
Thus, the variance of the profile is 0.2179.
Answer:
so this is what I got (i could be wrong)-- H=8 G=21 F=24 E=2
Step-by-step explanation:
3(7+10) = G + 30
21 + 30 = G+30 (mutilpy-3 times 7 and 10)
minus 30 from both sides
21=G
5(3 + H) = 15 + 45
15 + 5H = 15 + 45 (multipy- 5 times 3 and H)
minus 15 from both sides
5H = 45
divde both sides by 5
H=8
For E all you have to do is list out all the multiples that makeup 22 and 30 and you should find that 2 is the answer
1 - 2/7 - 1/3
= 21/21 - 6/21 - 7/21
= 8/21
= 1/3