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Reil [10]
3 years ago
6

How do I work this out???

Mathematics
1 answer:
Finger [1]3 years ago
7 0
Okay so form a right angle triangle and the angle of that is 65 as it is right angle so 90 - 25= 65. label the sides like the pic below. 

we have the hypothenuse as well as the angle and we are trying to find the o(opposite side) 

o/h =sin
sin 65=23/h
sin 65 = 23/x
23/sin 65=x 
x=25.4
how high the kite is above ground is :
= 25.4 +1.2
 =26.6

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Apr 24,8:28:53 AM<br> Find the 98th term of the arithmetic sequence -10,-8, -6, ...
Nata [24]

Answer: 184

Step-by-step explanation:

The nth term of am arithmetic sequence is calculated as:

Nth term= a+(n-1)d

where a = first term

d = common difference

a = -10

d = -8 -(-10) = -8+10 = 2

98th term= a+(n-1)d

= -10 + (98-1)(2)

= -10 + (97×2)

= -10 + 194

= 184

The 98th term of the arithmetic sequence is 184

6 0
3 years ago
What is the value of x=2x + 9 = -27
Sergio039 [100]
<h3>I'll teach you how to solve 2x + 9 = -27</h3>

-----------------------------------------------------

2x + 9 = -27

Subtract 9 from both sides:

2x+9-9 = -27-9

SImplify:

2x=-36

Divide both sides by 2:

2x/2 = -36/2

Simplify:

x= -18

Your Answer Is x= -18

plz mark me as brainliest if this helped :)

5 0
3 years ago
Read 2 more answers
Which statement is true?
natka813 [3]
Every square is a rectangle<span> because it is a quadrilateral with </span>all<span> four angles right angles.</span>
7 0
3 years ago
Order from least to greatest 0.5, 1/5, 0.35, 12/25, 4/5
sdas [7]
First change them all into either fractions or decimals. Decimals are probably easier though. 1/5 = 0.2; 12/25 = 0.48; 4/5 = 0.8 
Order: 0.2, 0.35, 0.48, 0.5, 0.8
Then you change the decimals that you converted back into the fraction form
Answer: 1/5, 0.35, 12/25, 0.5, 4/5
5 0
2 years ago
The polynomial of degree 4, P ( x ) has a root of multiplicity 2 at x = 4 and roots of multiplicity 1 at x = 0 and x = − 4 . It
Annette [7]

Answer: P(x) = {(x-4)^2} (x) (x+4)

Step-by-step explanation:

Let's start with the multiplicity of 2;

At multiplicity of 2; x=4.

Therefore, x - 4 is a factor of the function P(x).

Since it has a multiplicity of 2, we will rewrite the factor as (x-4)^2

Now for the multiplicity of 1.

At this multiplicity of 1, x= 0 and - 4.

Therefore, the factors are x-0 and x+4

Since multiplicity of 1, the factors remain as they are without any additional root on top.

Therefore, the factors of the polynomial p(x) are (x-4)^2 and x and x+4.

And solution of P(x) in factor form will be: P(x) = {(x-4)^2} (x) (x+4)

7 0
3 years ago
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