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Alona [7]
3 years ago
11

Which polysaccharides are used for STRUCTURE and SUPPORT in cells?

Chemistry
1 answer:
zhenek [66]3 years ago
4 0

Answer:

In models describing the structure of the plant cell wall, the polysaccharide cellulose,which only contains glucose,forms cable-like structures which are associated with interspersed hemicellulose polysaccharides which consist of glucose chains with xylose side groups. The pectin polysaccharides, containing ironic acids, have a more kinked ribbon-like structure and serve to link the cellulose polysaccharides together by providing a gel-like matrix,completing the cell wall structure.

Explanation:

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The atomic number of element Y is 119. What should be the atomic number of element X
elena-14-01-66 [18.8K]

Answer:

elment ? atómic 71⁰349⁹⁰291

3 0
3 years ago
If the moon resembled an asteroid, which theory would be most supported?
Law Incorporation [45]
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6 0
3 years ago
Which of the following is true about nuclear fission?
Ymorist [56]

Answer:

If you add the masses of all the products after fission, they are LESS than the mass of the reactants.

Explanation:

A nuclear fission reaction is a radioactive reaction which in which a heavy nucleus spontaneously disintegrates into 2 lighter nuclei and some neutrons with a release of large amount of energy.

When nuclear fission occurs, a mass deficit between the decaying nuclei and the product occurs. It is this mass that actually yields the energy that is produced as a by product of the reaction.

4 0
4 years ago
HELP! PLEASE! ASAP! Manganese(III) fluoride, MnF3, can be prepared by the following reaction:
Crank

Answer:

14.336 g MnF₂

Explanation:

number of moles = mass / molecular weight

number of moles of MnI₂ = 55 / 309 = 0.178 moles

number of moles of F₂ = 55 / 38 = 1.447 moles

From the reaction and the number of moles calculated we deduce that the fluorine F₂ is a limiting reactant.

So:

if        13 moles of F₂ reacts to produce 2 moles of MnF₃

then   1.447 moles of F₂ reacts to produce X moles of MnF₃

X = (1.447 × 2) / 13 = 0.223 moles of MnF₃ (100% yield)

For 57.2% yield we have:

number of moles of MnF₃ = (57.2 / 100) × 0.223 = 0.128 moles

mass = number of moles × molecular weight

mass of MnF₃ = 0.128 × 112 = 14.336 g

3 0
3 years ago
What is the [H3O+] in a solution of pH 0.60?
madam [21]

Answer:

.25

Explanation:

H+=10^-pH

- Hope that helps! Please let me know if you need further explanation.

6 0
4 years ago
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