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Tanya [424]
4 years ago
10

3(8⋅7−45)+5(6⋅4−1) Just checking to see if it is right

Mathematics
2 answers:
AveGali [126]4 years ago
6 0

Answer: 148

Step-by-step explanation:

tino4ka555 [31]4 years ago
4 0

Answer:

3(8⋅7−45)+5(6⋅4−1) = 148

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70

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Which numbers are the extremes of the proportion shown below?
wolverine [178]

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A 3 and 8

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if a/b=c/d, the extremes are "a" and "d". The means would then be "b" and "c"

8 0
2 years ago
A rectangular box has length 20cm, width 6cm and height 4cm. find how many cubes of size 2cm that will fit into the box.​
Papessa [141]

<u>Answer:</u>

\boxed{\pink{\sf The \ number \ of \ cubes \ that \ can \ be \ fitted \ is 60 .}}

<u>Step-by-step explanation:</u>

Given dimensions of the box = 20cm × 6cm × 4cm .

Dimension of the cube = 2cm × 2cm × 2cm .

Therefore the number of cubes that can be fitted into the box will be equal to the Volume of box divided by the Volume of the cube. So ,

\boxed{\red{\bf \implies No. \ of \ cubes \ = \dfrac{Volume \ of \ box}{Volume \ of \ cube }}}

\bf \implies n_{cubes} = \dfrac{20cm \times  6cm \times 4cm .}{2cm  \times 2cm  \times 2cm } \\\\\bf\implies n_{cubes}  = 10 \ times 3cm \times 2cm \\\\\implies \boxed{\bf n_{cubes}= 60 }

<h3><u>Hence</u><u> the</u><u> </u><u>number</u><u> </u><u>of</u><u> </u><u>cubes</u><u> </u><u>that</u><u> </u><u>can</u><u> </u><u>be</u><u> </u><u>fitted</u><u> </u><u>in</u><u> the</u><u> </u><u>box </u><u>is</u><u> </u><u>6</u><u>0</u><u> </u><u>.</u></h3>

6 0
3 years ago
PLS HELP WILL MARK U BRAINLIEST
Olenka [21]
They are identical lines so they have infinity pairs

3 0
3 years ago
2.36 grams=? hectograms
defon
2.36 g = 0.0236 hg

I hope this helped you.
Have a great day!
5 0
3 years ago
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