F(x)= 3x + 1
f(x)= 3(3) + 1
= 9 + 1
= 10
g(x)= 4x - 5
= 4(3) - 5
= 12 - 5
= 7
So... A. f(x) is greater when x=3
I think it is 32, bc the value of x is 20 so your problem would look like this; 2 ( (20) - 4 )
Number: n
square of number: n^2
sum of n and n^2 is n+n^2=20
Rewriting this equation, we get n^2+n-20=0 = (n+5)(n-4) = 0
Then n+5=0 and n-4=0, so n = -5 and n = 4.
You must check both results. It could happen that both are correct, or that only one is correct.
Answer:
To add integers with different signs, keep the sign of the number with the largest absolute value and subtract the smallest absolute value from the largest.
Step-by-step explanation:
Answer:
y=3
Step-by-step explanation:
y + 3 = –y + 9
Add y to each side
y+y + 3 = –y+y + 9
2y+3 = 9
Subtract 3 from each side
2y+3-3 = 9-3
2y = 6
Divide by 2
2y/2 = 6/3
y =3
