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3 years ago

Physical science : Find the speed of an object that covers 400 km in 5 hr.

1 answer:

8 0

speed=distance / time.

Data:
distance=400 Km
time=5 hours.

Speed=400 Km / 5 hours=80 km/hr.

Answer: b. 80 Km/hr.

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Nine thousand and ninety

loris [4]

Answer:huh?

Step-by-step explanation:

Answer:huh?

8 0

3 years ago

Read 2 more answers

3. Which list below shows the number of medals that one nation's team won at the Olympics. What is the ratio of gold medals to t

vovikov84 [41]

Answer:

The ratio of gold medals to the total number of medals that the team won is 34 to 103.

The correct option is B. 34 to 103

Step-by-step explanation:

From the question, the team of one nation has won 34 Gold, 30 Silver, and 39 Bronze medals.

To determine the ratio of gold medals to the total number of medals that the team won,

First, we will determine the total number of medals that the team won, which is the sum of the numbers of each medal won. That is

Total number of medals = 34 + 30 + 39 = 103

Therefore, total number of medals = 103

Now, for the ratio of gold medals to the total number of medals that the team won

Number of gold medals won = 34

Hence, the ratio of gold medals to the total number of medals that the team won is 34 to 103

4 0

3 years ago

Can someone help me with algebra 2 with an explanation?

sammy [17]

Answer: This took me a long time to type, hope you read it and find it helpful and easy to understand...

1. $x=1$

2. $x=\frac{3}{2}$

3. $x=1$

4. $x=\frac{6}{5}$

Step-by-step explanation:

$\frac{1}{x}-\frac{x-2}{3x}=\frac{4}{3x}$

To make it easier to add / subtract fractions, we are looking for common denominators. I can see that if I move the fraction on the left with a denominator 3x to the right, I'll be able to add two equations with like denominator.

Let's add $\frac{x-2}{3x}$

$\frac{1}{x}=\frac{4}{3x}+\frac{x-2}{3x}$

Add the numerators and keep the same denominator.

$\frac{1}{x}=\frac{4+x-2}{3x}$

$\frac{1}{x}=\frac{2+x}{3x}$

To get rid of the denominator x on the left side, we can multiply by x.

$(x)\frac{1}{x}=\frac{2+x}{3x}(x)$

$1=\frac{2+x}{3}$

Now multiply by 3.

$(3)1=\frac{2+x}{3}(3)$

$3=2+x$

Subtract 2.

$3-2=x\\1=x$

The value of x is 1.

Proof.

$\frac{1}{x}-\frac{x-2}{3x}=\frac{4}{3x}$

$\frac{1}{1}-\frac{1-2}{3(1)}=\frac{4}{3(1)}$

$1-\frac{-1}{3}=\frac{4}{3}$

$1+\frac{1}{3}=\frac{4}{3}$

$\frac{1*3+1}{3} =\frac{4}{3}\\\frac{4}{3}=\frac{4}{3}$

I can't show the proof to the following problems because I have a 5000 character limit.

-----------------------------------------------------------------------------------------

$\frac{5x-5}{x^2-4x} -\frac{5}{x^2-4x}=\frac{1}{x}$

Again, we have like denominators, therefore, we can simply subtract the numerators and keep the same denominator.

$\frac{5x-5-5}{x^2-4x}=\frac{1}{x}$

$\frac{5x-10}{x^2-4x}=\frac{1}{x}$

Again, we can multiply by x to get rid of the x in the denominator.

$(x)\frac{5x-10}{x^2-4x}=\frac{1}{x}(x)$

Do not distribute the x in the numerator yet because we're gonna eliminate it later.

$\frac{(x)(5x-10)}{x^2-4x}=1$

Factor the denominator.

$\frac{(x)(5x-10)}{(x)(x-4)}=1$

Simplify x's.

$\frac{5x-10}{x-4} =1$

Multiply by x-4 to get rid of the denominator.

$(x-4)\frac{5x-10}{x-4} =1(x-4)$

$5x-10=x-4$

Add 10

$5x=x-4+10$

Subtract x

$5x-x=-4+10$

Combine like terms;

$4x=6$

Divide by 4.

$\frac{4x}{4}=\frac{6}{4}$

$x=\frac{6}{4}$

Simplify by 2.

6/2 = 3

4/2 = 2

$x=\frac{3}{2}$

-----------------------------------------------------------------------

$\frac{x^2-7x+10}{x}+\frac{1}{x}=x+4$

Same denominator, add numerators.

$\frac{x^2-7x+10+1}{x}=x+4$

$\frac{x^2-7x+11}{x}=x+4$

Multiply by x to get rid of the x.

$(x)\frac{x^2-7x+11}{x}=(x+4)(x)$

$x^2-7x+11=x^2+4x$

Subtract $-x^2-4x$

$x^2-7x+11-x^2-4x=0$

Combine like terms;

$-11x+11=0$

Subtract 11.

$-11x=-11$

Divide by -11

$x=\frac{-11}{-11} \\x=1$

-------------------------------------------------------------------------

$\frac{x^2+7x+10}{5x-30}+\frac{x}{x-6}=\frac{x^2-13x+40}{5x-30}$

It's easier if you move the operation with denominator x+6 to the right side with negative sign and bring the operation on the right side to the left side with negative sign as well.

$\frac{x^2+7x+10}{5x-30}-\frac{x^2-13x+40}{5x-30}=-\frac{x}{x-6}$

Now, since we have the same denominators, we can simply subtract numerators.

$\frac{x^2+7x+10-(x^2-13x+40)}{5x-30} =-\frac{x}{x-6}$

Distribute the negative sign.

$\frac{x^2+7x+10-x^2+13x-40}{5x-30} =-\frac{x}{x-6}$

Combine like terms;

$\frac{20x-30}{5x-30}=-\frac{x}{x-6}$

Factor.

I can see that I can factor a 5 on both numerator and numerator. This will allow me to simplify them.

$\frac{(5)(4x-6)}{(5)(x-6)} =-\frac{x}{x-6}$

Simplify.

$\frac{4x-6}{x-6}=-\frac{x}{x-6}$

Multiply by x-6

$(x-6)\frac{4x-6}{x-6}=-\frac{x}{x-6}(x-6)$

This will simplify the denominators.

$4x-6=-x$

Add x and 6.

$4x+x=6\\$

Combine like terms;

$5x=6$

Divide by 5.

$x=\frac{6}{5}$

4 0

3 years ago

What is the value of the 30th term in the following arithmetic sequence? 12, 6, 0, -6, ... HELP!!!!

salantis [7]

30 times by 6 because it goes down by 6 which is 180 and take awat from 12 which is -168
And don't forget that it is a negative. so leave a minus before the number.

4 0

3 years ago

Read 2 more answers

A family drove to their grandmother's house after the average 200 miles per day

VMariaS [17]

Is that suppose to be the problem?

8 0

3 years ago