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zzz [600]
3 years ago
14

SA=πr^2-πr solve for r

Mathematics
1 answer:
blagie [28]3 years ago
5 0
A great time to apply the quadratic formula
for a quadratic equation
Ax^2 + Bx +C =0

then
x= \frac{-b\pm \sqrt{b^2-4ac}}{2a}
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True or False? 92x - x = 92
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Answer: False

Step-by-step explanation: 92x-x would be 91x.

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2x^2+13x=0 quadratic formula
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The mean of 4 numbers is 32. If three of the numbers are 15, 21, and 75, what is the value of the fourth number?
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The area of a square in square feet is
Sedaia [141]

Answer:

Part 1) The expression for the perimeter is P=4(25z-3) or  P=100z-12

Part 2) The perimeter when  z = 15 ft. is P=1,488\ ft

Step-by-step explanation:

Part 1)

we have

625z^{2}-150z+9

Find the roots of the quadratic equation

Equate the equation to zero

625z^{2}-150z+9=0

Complete the square

Group terms that contain the same variable, and move the constant to the opposite side of the equation

625z^{2}-150z=-9

Factor the leading coefficient  

625(z^{2}-(150/625)z)=-9

625(z^{2}-(6/25)z)=-9

Complete the square. Remember to balance the equation by adding the same constants to each side

625(z^{2}-(6/25)z+(36/2,500))=-9+(36/4)

625(z^{2}-(6/25)z+(36/2,500))=0

Rewrite as perfect squares

625(z-6/50)^{2}=0

z=6/50=0.12 -----> root with multiplicity 2

so

The area is equal to  

A=625(z-0.12)(z-0.12)=[25(z-0.12)][25(z-0.12)]=(25z-3)^{2}

The length side of the square is b=(25z-3)

therefore

The perimeter is equal to

P=4b

P=4(25z-3)

P=100z-12

Part 2) Find the perimeter when  z = 15 ft.

we have

P=100z-12

substitute the value of z

P=100(15)-12=1,488\ ft

4 0
3 years ago
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