Evaluate the given algebraic expression for x = 7 and y = 3. 2(x + y)2 A.)20 B.)42 C.)200 D.)400
2 answers:
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Answer:
Option: D is the correct answer.
D) 4
Step-by-step explanation:
A random draw is being designed for 210 participants.
If the winner is to be drawn using 10 balls numbered 0 through 9.
That is for the 210 participants we have to get a 210 unique numbers so that each participant winning chance is denoted by a unique number.This means that n balls are to be drawn out of the 10 balls such that we get total 210 choices irrespective of their order.
Hence, we have to find n such that:
A)
Now when n=10
we have:
Hence, option:A is incorrect.
B)
when n=6 we have:
C)
n=5
D)
n=4
So, either 4 or 6 balls can be drawn in order to obtain 210 choices but we are asked to find the minimum number of balls and as 4<6 .
Hence, a minimum of 4 balls need to be drawn so that each receives a unique number.