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Oksanka [162]
3 years ago
13

I need answers to both of the questions Please help

Mathematics
2 answers:
pashok25 [27]3 years ago
8 0

Answer:

1.) 192 minutes

2.) If it's the 9th day : 69 minutes

If it's the 10th day : 64 minutes

Step-by-step explanation:

1.) 5th Day - 32 minutes

32*6= 192 minutes on the 30th day.

2.) If it's the 9th day -

3rd Day - 23 minutes

23*3= 69 minutes

2.)If it's the 10th day -

5th day - 32 minutes

32*2= 64 minutes

jolli1 [7]3 years ago
4 0

Answer:

131 minutes, an = 15 + (n - 1)(4)

Step-by-step explanation:

each time she is increasing by 4 minutes

we can write this equation like this since we have the difference and the first part:

an = 15 + (n - 1)(4)

note

"an" (or ace of n)'s n is in subscript and is written just like a superscript but on the bottom

we can plug in this equation to find ace of 30 (a30)

15 + (30 - 1)(4)

15 + 29*4

116 + 15

a30 = 131

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Answer:

The correct answer is w = 52h

Step-by-step explanation:

Since you are trying to find Maya's hourly pay, you have to use the numbers that are given to you. The problem states that Maya earned $52 per hour, therefore the proportional relationship will be w = 52h.

Hope this helped! :)

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An electronics retailer offers an optional protection plan for a mobile phone it sells. Customers can choose
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$79

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That's the Khan Academy answer

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16. Write the inequality that is shown on the graph.
TiliK225 [7]

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2 years ago
Big Lots sells AA batteries for $ 5.88 you git a pack of 12. Walmart has the same batteries for $8.82 you git a pack of 18 batte
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ΔCAR has coordinates C (2, 4), A (1, 1), and R (3, 0). A translation maps point C to C' (3, 2). Find the coordinates of A' and R
shutvik [7]

Answer:

A'= (2,-1) and R'=(4,-2) under this translation.

Step-by-step explanation:

A translation in R^{2} is a mapping T from R^{2} to R^{2}  defined by T(x,y) = (x + v_1,y+v_2), where v=(v_1,v_2) is a fixed vector in R^{2}.

From the problem we know that T(2,4)=(3,2), so we need to find the values v_1 and v_2 such that  T(2,4) = (2 + v_1,4+v_2)=(3,2), so 3=2 + v_1 and 4+v_2=2, thus v_1=1 and v_2=2.

Then T(x,y) = (x + 1,y-2) and  

T(1,1)=(1+1,1-2)=(2,-1)=A'

T(3,0)=(3+1,0-2)=(4,-2)=R'

Therefore A'= (2,-1) and R'=(4,-2). The triangles CAR and C'Q'R' are shown in the figure below.

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