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babunello [35]
3 years ago
13

Line j goes through the point (-7, 5) and is perpendicular to 2x – 3y = -18. Find the equation of line j.

Mathematics
1 answer:
Alex777 [14]3 years ago
5 0

Answer:

3x + 2y = 31  

Step-by-step explanation:

Solve the given equation for y to determine the slope of this line:

-3y = -2x = -18, so that y = (2/3)x + 6.

Therefore, a line perpendicular to the given line has the slope -3/2, which is the negative reciprocal of this 2/3.

Using the slope-intercept formula y = mx + b and inserting the knowns (slope = m = -3/2, y = 5 and x = -7), we obtain:

5 = (3/2)(-7) + b, or (after multiplying all terms by 2):

10 = -21 + 2b, or 2b = 31, or b = 31/2.

Then the equation is y = (-3/2)x + 31/2.

Let's put this into standard form.  Multiply all terms by 2, obtaining:

2y = -3x + 31, or

3x + 2y = 31    This is the equation of the perpendicular line in question.

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What is the inverse of the function f(x) = 2x + 1?|
padilas [110]

Answer:

1st option

Step-by-step explanation:

let y = f(x) and rearrange making x the subject

y = 2x + 1 ( subtract 1 from both sides )

y - 1 = 2x ( divide both sides by 2 )

\frac{y-1}{2} = x

Change y back into terms of x with x being the inverse h(x)

h(x) = \frac{x-1}{2} = \frac{1}{2} x - \frac{1}{2}

6 0
2 years ago
#4 home do I find which one it is?
lina2011 [118]
\bf \begin{array}{lllll}
solutions&graphs&slopes\\
----&----&----\\
\textit{exactly one}&
\begin{array}{llll}
\textit{the two lines intersect}\\
\textit{at one point}
\end{array}&\textit{different slopes}\\\\
infinitely\quad many&
\begin{array}{llll}
\textit{the two lines coincide}\\
\textit{one is right on top}\\
\textit{ of the other}
\end{array}&
\begin{array}{llll}
\textit{equal slopes}\\
\textit{equal y-intercepts}
\end{array}
\end{array}

\bf \textit{no solution}\qquad\quad &\textit{lines are parallel} \qquad &
\begin{array}{llll}
\textit{equal slopes}\\
\textit{different y-intercepts}
\end{array}
\end{array}

for example, let's look at the first set

y+3x =5   or  y = -3x+ 5
and               y = -3x + 2
                    y =  m  + b

the slopes are equal, the y-intercepts differ
that means, they're just parallel lines, no solution
8 0
3 years ago
Solve for x: -a + 3b > 5
Viefleur [7K]
Theres an app called photomath thats useful for these kinds of problems
8 0
3 years ago
Some help me with this math problem
Anestetic [448]
Only the upper-left statement is NOT true.
5 0
3 years ago
Find two points on the line to be graphed 2y+16=0
yarga [219]
Y=-8 so any x with the coordinate -8 for y i guess. 
4 0
3 years ago
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