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a_sh-v [17]
3 years ago
9

What is the area of the triangle

Mathematics
2 answers:
raketka [301]3 years ago
7 0
A = 1/2b*h = 0.5*9*10 = 45 m^2
Ludmilka [50]3 years ago
4 0
Wouldn't the formula be a×b/2?
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12 is 8% of what number?
jeka57 [31]
We can also say this in another way ... (8% of what number is 12?)
let a be the number of which 8 % is 12 ....
<span>8/100 x a =12 </span>
<span>a=12 x 100/8 </span>
<span>a=(6/4) x 100 </span>
<span>a=(3/2) X 100
a = 150  </span>

<span>now if u want to check your answer.. substitute the value of a .....</span>
<span>(8/100) x 150=12 ....

Hope it helps !!!</span>
7 0
3 years ago
Read 2 more answers
Jamie needs to determine the distance across a river. She selects a rock, R. on the opposite river bank. She finds a tree, T. on
Elina [12.6K]

9514 1404 393

Answer:

  RT = 75 yards

Step-by-step explanation:

Triangle TCB is congruent to triangle TCR by ASA. (Side TC is between angles T and C.)

Then RT = BT = 75 yards.

4 0
3 years ago
Quadratic Formula to solve the equation x^2- 4x = - 7
mylen [45]

roots of the equation x^2- 4x = - 7 are  2+3i and 2-3i

What are the natures of root of quadratic equation?

Case I: 4ac > b^2

The roots of the quadratic equation ax^2 + bx + c = 0are real and unequal when a, b, and c are real numbers, a 0, and the discriminant is positive.

Situation II:  b^2-4ac =0

The roots and of the quadratic equationax^2 + bx + c = 0  are real and equal when a, b, and c are real numbers, a 0, and the discriminant is zero.

Case III: b^2-4ac<0

The quadratic equation ax^2 + bx + c = 0 has roots when a, b, and c are real numbers, a 0, and the discriminant is negative, but these roots are not equal and are not real. We refer to the roots in this instance as fictitious.

Case IV: Perfect square and b^2 - 4ac > 0

The roots of the quadratic equation ax^2 + bx + c = 0  are real, rational, and unequal when a, b, and c are real numbers, a 0, and the discriminant is positive and perfect square.

Quadratic Formula x={\frac {-b\pm {\sqrt {b^{2}-4ac}}}{2a}}

x^2- 4x = - 7

x^2-4x+7=0

Here a = 1 , b = -4 , c = 7

using quadratic formula

x={\frac {-(-4)\pm {\sqrt {(-4)^{2}-4(1)(7)}}}{2(1)}}

x={\frac {4\pm {\sqrt {-12}}}{2}}

x={\ {2\pm {\ 3i}}

Learn more about quadratic equation from the link below

brainly.com/question/2279540

#SPJ1

8 0
1 year ago
I need help being guided through this question. I thought it was SAS. But not sure.​
topjm [15]

Answer:

ASA

Step-by-step explanation:

You know the angle of 90 degrees on both sides. Then you see they have the same side, and then you see they have the same angle (vertical angles)

3 0
3 years ago
What is the slope of the line represented by the equation y = 4/5 x -3? A-1 B-4/5 C4/5 D3
Cerrena [4.2K]

Option C

<u>ANSWER: </u>

For the given equation slope is \frac{4}{5} so the correct option is c.

<u>SOLUTION: </u>

Given, line equation is $y=\frac{4}{5} x-3$

We need to find the slope of the given equation.

Above given equation is in the form of slope intercept form, i.e. y = mx + c

Where m is the slope and c is the intercept made on axis by this line.

By comparing the given equation and the general form, we can conclude that,  m = \frac{4}{5} and c = -3

hence, for the given equation slope is \frac{4}{5}. so the correct option is c.

8 0
4 years ago
Read 2 more answers
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