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Liono4ka [1.6K]
3 years ago
14

The sum of four consecutive integers is 18 find the largest consecutive integer

Mathematics
2 answers:
Whitepunk [10]3 years ago
5 0

Answer:

The largest consecutive integer is 6

Step-by-step explanation:

Let n, n +1, n+2, and n+3 are the  four consecutive integers

The sum of four consecutive integers is 18

n + n + 1 + n + 2 + n + 3 = 18

4n + 6 = 18

4n = 12

n = 3

The sum of four consecutive integers: 3, 4 , 5 , 6

Answer:

The largest consecutive integer is 6

neonofarm [45]3 years ago
5 0

The sum of 3 consecutive integers can be represented as

X → <em>first integer</em>

X + 1 → <em>second integer</em>

X + 2 → <em>third integer</em>

X + 3 → <em>fourth integer</em>

<em />

Since the sum of our three consecutive integers is 18, our equation will read...

X + X + 1 + X + 2 + X + 3 = 18

If we simplify on the left, our equation will read

<h2>4x + 6 = 18</h2><h2>       -6    -6    ← subtract 6 on both sides</h2><h2 /><h2>       4x = 12</h2><h2>        X = 3</h2>

X + 3 = largest integer

3 = 3 = 6

Therefore, the largest integer is 6.

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add the term that makes the given expression into a perfect square. write the result as the square of a bracketed expression c s
Molodets [167]
<h2>Perfect Squares</h2>

Perfect square formula/rules:

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Trinomials are often organized like ax^2+bx+c.

The <em>b</em> value in this case is <em>c</em>, and it will always equal the square of half of the <em>b</em> value.

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<h2>Solving the Question</h2>

We're given:

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In a trinomial, we're given the ax^2 and bx values. <em>a</em> in this case is 1 and <em>b</em> in this case is 4. To find the third value by dividing 4 by 2 and squaring the quotient:

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To write this as the square of a bracketed expression, we can follow the rule a^2-2ab+b^2=(a-b)^2:

(c-2)^2

<h2>Answer</h2>

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(c-2)^2

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2 years ago
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muminat

Answer:

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Step-by-step explanation:

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astraxan [27]
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