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Liono4ka [1.6K]
3 years ago
14

The sum of four consecutive integers is 18 find the largest consecutive integer

Mathematics
2 answers:
Whitepunk [10]3 years ago
5 0

Answer:

The largest consecutive integer is 6

Step-by-step explanation:

Let n, n +1, n+2, and n+3 are the  four consecutive integers

The sum of four consecutive integers is 18

n + n + 1 + n + 2 + n + 3 = 18

4n + 6 = 18

4n = 12

n = 3

The sum of four consecutive integers: 3, 4 , 5 , 6

Answer:

The largest consecutive integer is 6

neonofarm [45]3 years ago
5 0

The sum of 3 consecutive integers can be represented as

X → <em>first integer</em>

X + 1 → <em>second integer</em>

X + 2 → <em>third integer</em>

X + 3 → <em>fourth integer</em>

<em />

Since the sum of our three consecutive integers is 18, our equation will read...

X + X + 1 + X + 2 + X + 3 = 18

If we simplify on the left, our equation will read

<h2>4x + 6 = 18</h2><h2>       -6    -6    ← subtract 6 on both sides</h2><h2 /><h2>       4x = 12</h2><h2>        X = 3</h2>

X + 3 = largest integer

3 = 3 = 6

Therefore, the largest integer is 6.

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Answer:

B

Step-by-step explanation:

5a^2 - 44 = 81                     Add 44 to both sides

5a^2 = 81 + 44                    Collect like terms

5a^2 = 125                          Divide both sides by 5

a^2 = 125/5                  

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√a^2 = √25

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a = -5

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UkoKoshka [18]

Answer: the answer is x=36

Step-by-step explanation:

Simplify  \frac{1}{8}(x-4)

8

1

​

(x−4)  to  \frac{x-4}{8}

8

x−4

​

.

-\frac{x-4}{8}=-4

−

8

x−4

​

=−4

2 Multiply both sides by 88.

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−x+4=−4×8

3 Simplify  4\times 84×8  to  3232.

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7 Multiply both sides by -1−1.

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