X=year
y=$
y=200(1.003)^12x
3.6%->.036/12 (compounded monthly)
=0.003+1
y=200(1.003)^12(1) (1 year)
=$207.31999
BUT
200•12 ($200 deposited every month)
=$2400
2400+207.3199=
$2607.32
We know, Volume of a Sphere = 4/3 πr³
v = 4/3 * 3.14 * 27³
v = 4/3 * 3.14 * 19,683
v = 82406.16 feet³
In short, Your Answer would be Option B
Hope this helps!
Let's solve number 7 <span>step-by-step.
</span><span><span>y/23</span>=7
</span>Step 1: Multiply both sides by 23.
<span><span>y/23</span>=7
</span><span><span><span>(<span>y23</span>)</span>*<span>(23)</span></span>=<span><span>(7)</span>*<span>(23)
</span></span></span><span>y=<span>161 is our answer.
</span></span>Let's solve number 8 step-by-step.
<span>n−4.85=12.6
</span>Step 1: Add 4.85 to both sides.
<span>n−4.85+4.85=12.6+4.85
</span>n=17.45 is our answer.
<span>
</span>Let's solve number 12 step-by-step.
<span><span>m/5</span>=8
</span>Step 1: Multiply both sides by 5.
<span><span>m/5</span>=8
</span><span><span><span>(<span>m/5</span>)</span>*<span>(5)</span></span>=<span><span>(8)</span>*<span>(5)
</span></span></span><span>m=40 is our answer.
</span><span>
</span>Let's solve number 16 step-by-step.
<span><span>a/12</span>=8
</span>Step 1: Multiply both sides by 12.
<span><span>a/12</span>=8
</span><span><span><span>(<span>a/12</span>)</span>*<span>(12)</span></span>=<span><span>(8)</span>*<span>(12)
</span></span></span><span>a=<span>96 is or answer.</span></span>
Answer:
- <u>Option C. The Network C sample.</u>
Explanation:
The variability of a sample may be described by using some common statistics like the variance and the standard deviation.
The variance and the standard deviation measure the difference between the values of the data and the mean. The variance is the average square of those differences or deviations. The standard deviation is the square root of the variance.
Thus, both variance and deviations, being an average of the differences of the data from the mean contain the number of data in the denominator of the equation.
That lets you know to conclude that the larger the number of data (the larger the sample) the smaller the variance and the standard deviation, this is the lower the variability of the data.
Hence, Network C, which has the greatest number of voters sampled (1,800) is likely to have the least variability.
