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ExtremeBDS [4]
4 years ago
12

Quiz 6. Simplify the expression. 4 (10 – 4)² + 4) A6 B 36 D 12

Mathematics
2 answers:
larisa86 [58]4 years ago
4 0

This is all about operations priority! We have to perform the operations in the right order, remembering that parentheses come first, then powers, then multiplications and then additions:

Start with

4(10-4)^2+4

Perform the operations inside parenthesis first:

4\cdot 6^2+4

Perform the square:

4\cdot 36+4

Perform the product:

144+4

Perform the sum:

148

Note: you have an extra parenthesis at the end, and none of the options meets the result. I'm afraid that there's a typo in the question, but this should still give you a valid strategy to solve the actual exercise.

evablogger [386]4 years ago
3 0
Answer=148
You subtract the numbers
Then evaluate the power
Then you multiply the numbers
Finally you add the numbers
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Answer:

13.  36a^2b^4π  

14. 16x^3y^4π

15. -\frac{c^3}{4a^7b^3}

Step-by-step explanation:

13.

A = π * r^2

r = 6ab^2

A = π*  (6ab^2)^2

A = π * (6ab^2)(6ab^2)

A = π * 36a^2b^4

A = 36a^2b^4π  

14.

V = π * r^2 * h

r = 2x

h = 4xy^4

V = π * (2x)^2 * 4xy^4

V = π * 4x^2 * 4xy^4

V = π * 16x^3y^4

V = 16x^3y^4π

15. \frac{3a^{-4}b^2}{-12a^3b^5c^{-3}} = -\frac{c^3}{4a^7b^3}

\frac{3a^{-4}b^2}{-12a^3b^5c^{-3}}

\frac{a^{-4}}{-4a^3b^5c^{-3}}

\frac{b^2}{-4^{3+4}b^5c^{-3}}

\frac{b^2}{-4^7b^5c^{-3}}

\frac{1}{-4a^7b^{5-2}c^{-3}}

\frac{1}{-4a^7b^3c^{-3}}

\frac{c^3}{-4a^7b^3}

-\frac{c^3}{4a^7b^3}

Hope this helps!

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3 years ago
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storchak [24]
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A bottle rocket is shot off a bridge into the stream below. The height of the rocket (in feet) above
nalin [4]

The correct model of the height of rocket above water is;

h(t) = -16t² + 96t + 112

Answer:

time to reach max height = 3 seconds

h_max = 256 ft

Time to hit the water = 7 seconds

Step-by-step explanation:

We are given height of water above rocket;

h(t) = -16t² + 96t + 112

From labeling quadratic equations, we know that from the equation given, we have;

a = -16 and b = 96 and c = 112

To find the time to reach maximum height, we will use the vertex formula which is; -b/2a

t_max = -96/(2 × -16)

t_max = 3 seconds

Thus, maximum height will be at t = 3 secs

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h_max = h(3) = -16(3)² + 96(3) + 112

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h_max = 256 ft

Time for it to hit the water means that height is zero.

Thus;

-16t² + 96t + 112 = 0

From online quadratic formula, we have;

t = 7 seconds

7 0
3 years ago
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