Ask question

Ask question

All categories

3 years ago

14

The probability of waiting 4 minutes or longer for checkout at a particular supermarket counter is 0.1. On a given day, a man an

d his wife decide to shop individually at the market, each checking out at different counters. They both reach the counters at the same time.

1 answer:

Vedmedyk [2.9K]3 years ago

3 0

Answer:

Step-by-step explanation:

Hope this photo will find you well

Good day!

You might be interested in

Explain step by step how to use the horizontal method the multiple the two polynomials

MatroZZZ [7]

Answer:

Step-by-step explanation:

Multiply each term of the first polynomial with the second polynomial. Then combine the like terms.

(3a<em>² + 5a - 2)* (5a² -3a + 4)</em>

<em> = 3a² *(5a² -3a + 4) + 5a*(5a² -3a + 4) - 2*(5a² -3a + 4)</em>

<em>=3a²*5a² - 3a*3a² + 4*3a² + 5a*5a² - 3a*5a + 4*5a + 5a²*(-2) - 3a*(-2) + 4*(-2)</em>

<em>=15a⁴ - 9a³ + 12a² + 25a³ - 15a² + 20a - 10a² + 6a - 8</em>

<em>= 15a⁴ </em><u><em>- 9a³ + 25a³</em></u><em> +</em><u><em> 12a² - 15a² - 10a²</em></u><em> +</em><u><em> 20a +6a </em></u><em>- 8</em>

<em>= 15a⁴ + 16a³ - 13a² +26a - 8</em>

4 0

2 years ago

There is a markup of 40% on the original price of a fan. If the fan was sold for $42, what was its original price

Akimi4 [234]

Answer: 21$ that is the answer

Step-by-step explanation:

4 0

2 years ago

X^3 times x^? equals to x^17 <br><br> what’s the missing exponent?

ElenaW [278]

Answer:

14

Step-by-step explanation:

The applicable rule of exponents is ...

(a^b)(a^c) = a^(b+c)

__

You have ...

(x^3)(x^a) = x^17

x^(3+a) = x^17

Equating exponents, we get ...

3 +a = 17

a = 14

The missing exponent is 14.

5 0

3 years ago

WHAT DEFINES THE SOLUTION SET FOR THE INEQUALITY -X/2 +4<12 ? DUE BY 10:50

Marrrta [24]

-x/2+4<12

-4 -4

-x/2<8

*2 *2

-x<16

/-1 /-1

x<-16

---

hope it helps

4 0

2 years ago

Explain how to multiply the following whole numbers 21 x 14

Lesechka [4]

Answer:

$\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}$

________

$\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}$

Step-by-step explanation:

Given

$21\:\times \:14$

Line up the numbers

$\begin{matrix}\space\space&2&1\\ \times \:&1&4\end{matrix}$

Multiply the top number by the bottom number one digit at a time starting with the ones digit left(from right to left right)

Multiply the top number by the bolded digit of the bottom number

$\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}$

Multiply the bold numbers: 1×4=4

$\frac{\begin{matrix}\space\space&2&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&4\end{matrix}}$

Multiply the bold numbers: 2×4=8

$\frac{\begin{matrix}\space\space&\textbf{2}&1\\ \times \:&1&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&8&4\end{matrix}}$

Multiply the top number by the bolded digit of the bottom number

$\frac{\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&8&4\end{matrix}}$

Multiply the bold numbers: 1×1=1

$\frac{\begin{matrix}\space\space&\space\space&2&\textbf{1}\\ \space\space&\times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&\space\space&8&4\\ \space\space&\space\space&1&\space\space\end{matrix}}$

Multiply the bold numbers: 2×1=2

$\frac{\begin{matrix}\space\space&\space\space&\textbf{2}&1\\ \space\space&\times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&\space\space&8&4\\ \space\space&2&1&\space\space\end{matrix}}$

Add the rows to get the answer. For simplicity, fill in trailing zeros.

$\frac{\begin{matrix}\space\space&\space\space&2&1\\ \space\space&\times \:&1&4\end{matrix}}{\begin{matrix}\space\space&0&8&4\\ \space\space&2&1&0\end{matrix}}$

adding portion

$\begin{matrix}\space\space&0&8&4\\ +&2&1&0\end{matrix}$

Add the digits of the right-most column: 4+0=4

$\frac{\begin{matrix}\space\space&0&8&\textbf{4}\\ +&2&1&\textbf{0}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{4}\end{matrix}}$

Add the digits of the right-most column: 8+1=9

$\frac{\begin{matrix}\space\space&0&\textbf{8}&4\\ +&2&\textbf{1}&0\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{9}&4\end{matrix}}$

Add the digits of the right-most column: 0+2=2

$\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}$

Therefore,

$\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}$

________

$\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}$

6 0

3 years ago